Answer:
60 minutes for the larger hose to fill the swimming pool by itself
Step-by-step explanation:
It is given that,
Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.
takes 30 minutes for the larger hose to fill the swimming pool by itself
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
<u>To find LCM of 20 and 30</u>
LCM (20, 30) = 60
<u>To find the efficiency </u>
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
x = 60/30 =2
x + y = 60 /20 = 3
Therefore efficiency of y = (x + y) - x =3 - 2 = 1
so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes
Answer:
See picture attached.
Step-by-step explanation:
Start with the y-intercept of -2 and plot that on the graph. Then, use the slope of 1/2x to plot more points to help you draw the line. Remember rise over run. Go up one from the y-intercept and right two. If you need to, you can also go down one and left two.
Hope this makes sense.
Answer:
HI the answer is
Step-by-step explanation:
just put the answer who cares
Answer:
the original area is 64ft squared or 169ft squared more perdurable 64
Step-by-step explanation:
(x-2)(x+7)=90
x^2 +5x -14=90
x^2 +5x -14 -90=90-90
x^2 +5x -104=0
factor it out
(x−8)(x+13)=0
so 8 or -13
The point would become (8,2)
3+5=8
4-2=2
