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grigory [225]
3 years ago
7

a tank holds 480 gallons of fuel. if it drained at a rate of 120 gallons Per minute, it will be empty in __ seconds

Mathematics
2 answers:
WINSTONCH [101]3 years ago
6 0
240 seconds, 60 times 4 is 480. there is 60 seconds in a minute, times that by 4.
yaroslaw [1]3 years ago
4 0

Answer:240 seconds

Step-by-step explanation:

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2x-1/4(12x+4)=3 Step 1: 2x+3x+1=3 Step 2: 5x+1=3 Step 3: 5x+1-1=3-1 Step 4: 5x=2 Which step was the error made and why?
VashaNatasha [74]

step 1

2x-1/4(12x+4)=3

2x-3x-1=3

4 0
3 years ago
X=(y)/(y-3) make y the subject
Liula [17]

Answer:

\displaystyle y=\frac{3x}{x-1}

Step-by-step explanation:

<u>Solving Equations</u>

We have the expression:

\displaystyle x=\frac{y}{y-3}

And it's required to make y the subject.

It can be done by isolating y on the left side of the equation and the rest of the expression on the right side.

The first step is removing the denominator by multiplying both sides by y-3:

\displaystyle (y-3)x=(y-3)\frac{y}{y-3}

Simplifying the right side:

\displaystyle (y-3)x=y

Remove the parentheses:

yx-3x=y

Move the y's to the left side and the rest of the expression to the right side:

yx-y=3x

Factor out y:

y(x-1)=3x

Divide by x-1:

\mathbf{\displaystyle y=\frac{3x}{x-1}}

7 0
3 years ago
How do we write this in scientific notation?
marusya05 [52]

Answer:

The answer is Sodium chloride.

7 0
3 years ago
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A Simple random sample of 100 8th graders at a large suburban middle school indicated that 84% of them are involved with some ty
Setler [38]

Answer: a) (0.755, 0.925)

Step-by-step explanation:

Let p be the population proportion of 8th graders are involved with some type of after school activity.

As per given , we have

n= 100

sample proportion: \hat{p}=0.84

Significance level : \alpha= 1-0.98=0.02

Critical z-value : z_{\alpha/2}=2.33  (using z-value table)

Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

i.e. 0.84\pm (2.33)\sqrt{\dfrac{0.84(1-0.84)}{100}}

i.e. \approx0.84\pm 0.085

i.e. (0.84- 0.085,\ 0.84+ 0.085)=(0.755,\ 0.925)

Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)

3 0
4 years ago
For the function whose graph is shown, which is the correct formula for the function?
fiasKO [112]

Answer:

d

Step-by-step explanation:

Try using simple numbers like 1 as x and then try with the different functions until it works

8 0
4 years ago
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