Answer:
- <u><em>About 0.22</em></u>
Explanation:
There are two sets:
- Set W of incoming seniors who took AP World History, and
- Set E of incoming seniors who took AP European History
And there is a subset, which is the intersection of those two sets:
- Subset W ∩ E of senior students who took both.
The incoming seniors who are allowed to enroll in AP U.S. History, call them the subset S, is the set of those students that belong to W or E or both W ∩E.
By property of sets:
- S = W + E - W∩E = 175 + 36 - 33 = 178
Then, 178 out of 825 incoming seniors took one or both courses, and the desired probability of a randomly selected incoming senior is allowed to enroll in AP U.S. History is:
45/60=0.75. Speed*time=distance. 35(0.75)= 26.25 miles
The answer is 3√5. You use the distance formula: √((x2-x1)^2+(y2-y1)^2)
Answer:
Option A is correct .
Step-by-step explanation:
if in a question it is given that BC is equal to AB then only we can do like that...
Answer:
Step-by-step explanation:
As given Total Guavas = 40 ,
3 daughters,
Let share of Sharon = x
then by given condition ,
Naomi share = x+3 (3 more then Sharon
Also Kassie share = x+3+10 =x+13 (10 more then Naomi
Now
total shared = total
Naomi + Sharon + Kassie = 40
(x+3) +(x) +(x+13) =40
adding like terms with like we get ,
3x+16=40
3x=40-16
3x=24
x= 24/3
x= 8
hence Sharon share = x =8
Naomi share = x+3 =8+3 =11
Kassie share = x+13 = 8+13 = 21
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