Answer:
Kenny is 18 years old Andrew is 10 years old Tim is 30 years old and Cameron is 5 years old
Step-by-step explanation:
Let a be Kenny's age , b be Andrew's age , c be Tim's age , d be Cameron's age
( b < a , b<c , d<b)
Kenny is 8 years older than Andrewn = > a = b + 8 (1)
Tim is 3 times as old as Andrew => c = 3 . b (2)
Cameron is 5 years younger than Andrew => d = b-5 (3)
The combined age of the four is 63 => a+b+c+d = 63 (4)
(1),(2),(3),(4) => b+8 + b + 3b + b-5 = 63 <=> 6b + 3 = 63 <=> b = 10
=> a= 10+8 =18, c = 3 . 10 = 30, d= 5
Answer:
The answer is 1/9 ⇒ the second answer
Step-by-step explanation:
* In the exponential functions we have some rules
(1) b^(-m) = 1/(b^m) (for all nonzero real numbers b)
- If we have negative power we reciprocal the base
to get positive power
(2) (b^m)^n = b^(mn)
- If we have power over power we multiply them
* In our problem: 
- At first change 27 to b^n
∵ 27 = 3 × 3 × 3 = 3³
∴ 
* Lets use rule (2)
∴ 
⇒ 3 × -2/3 = -2
* Use rule (1)
∴ 
⇒ reciprocal the fraction to change the sig of the power
* The answer is 1/9
Can be number 1 or number 4 I am not sure but can be 4 but take your sedición
Decimal: 5.0
Fraction: 5/1
ac> bc is always true. This is beacuse c is multiplied to both a and b, and since a> b then ac will have a higher value than bc. Hence ac> bc is always true under the condition a> b.
