Answer:
C.8x - 16
Step-by-step explanation:
multiple 4 with 2x = 8x,
then multiple 4 with -4 = -16
add 8x and -16 the answer is 8x - 16
Answer: Barbara did not include a variable in the term
, which must represents the number of bottles of iced tea she needs to sell.
Step-by-step explanation:
Let be "x" the number of bottle of water Barbara needs to sell and "y" the number of bottle of iced tea she needs to sell.
She sells iced tea for $1.49 per bottle and water for $1.25 per bottle, so she can write the following equation in order to calculate the number of bottles she needs to sell to earn $100:
![1.25x + 1.49y = 100](https://tex.z-dn.net/?f=1.25x%20%2B%201.49y%20%3D%20100)
Since Barbara wrote this equation:
![1.25x + 1.49 = 100](https://tex.z-dn.net/?f=1.25x%20%2B%201.49%20%3D%20100)
We can conclude that the error Barbara made in writing the equation was: She did not include a variable in the term
, which must represents the number of bottles of iced tea she needs to sell.
Answer:
thanks
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Step-by-step explanation:
Answer:
y = m x + b equation of a straight line
m = (y2 - y1) / (x2 - x1) slope of line
m = (17 - 10) / (-36 - 48) = 7 / -84 = -1 / 12
y = -x / 12 + b equation of line
Or b = y + x / 12
If y = 10 and x = 48 then b = 10 + 48 / 4 = 14
if y = 17 and x = -36 then b = 17 - 36 / 12 = 14
So b = 14 and y = -x / 12 + 14
For any sort of pyramid or cone, the volume is 1/3 of the volume of a prism with the same base and height. Since the volume of a prism/cylinder is
![V=Bh](https://tex.z-dn.net/?f=V%3DBh)
, the volume of a pyramid/cone is
![V=\frac{1}3Bh](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D3Bh)
.
In this case, our base is a circle, which has a radius of 4 cm.
The area of a circle is
![A=\pi r^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2)
where r is the radius.
![A=\pi (4)^2=\pi (4\times4)=16\pi=B](https://tex.z-dn.net/?f=A%3D%5Cpi%20%284%29%5E2%3D%5Cpi%20%284%5Ctimes4%29%3D16%5Cpi%3DB)
We now know that our base is 16π cm.
We also know that our height is 9 cm.
Let's plug these into our volume formula.
![V=\frac{1}3\times16\pi \times9](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D3%5Ctimes16%5Cpi%20%5Ctimes9)
Use 3.14 to approximate pi as the question states. 16 × 3.14 = 50.24.
![V\approx\frac{1}3\times50.24\times9](https://tex.z-dn.net/?f=V%5Capprox%5Cfrac%7B1%7D3%5Ctimes50.24%5Ctimes9)
We could punch all of that into our calculator to get the same answer, but since 1/3 of 9 is clearly 3, let's just go with that.
![V\approx3\times50.24](https://tex.z-dn.net/?f=V%5Capprox3%5Ctimes50.24)