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2 years ago

A triangle has side lengths of 18 cm, 80 cm, and 81 cm. Classify it as acute, obtuse, or right.

Mathematics

2 answers:

nirvana33 [79]2 years ago

8 0

Answer:

The answer is:

C - Acute

Hope this helps :)

Step-by-step explanation:

hichkok12 [17]2 years ago

5 0

81^2 = 18 ^2 + 80^
6561 = 324 + 6400
6561 = 6724
It is not a right angle, since 18^2 + 80^2 does not equal 81^2.
So,
Using The law of cosines:
The largest angle C is opposite to the side c.
Therefore,
c^2 = a^2 + b^2 -2ab cosC 
Here,
c^2 < (a^2 + b^2)
cosC must be positive which makes C an acute angle.

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Jake paid $13.50 for admission to the country fair and bought 9 tickets to play games. If he spent a total of $36, what is the c

Sunny_sXe [5.5K]

Answer:

$2.50

Step-by-step explanation:

Jake's total expenditure is ...

total = admission + c × (number of tickets)

36 = 13.50 + 9c . . . an equation to solve

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Each ticket cost Jake $2.50.

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2 years ago

Mike runs for the president of the student government and is interested to know whether the proportion of the student body in fa

Alik [6]

Answer:

We conclude that the proportion of student body in favor of him is significantly less than or equal to 50%.

Step-by-step explanation:

We are given that Mike runs for the president of the student government and is interested to know whether the proportion of the student body in favor of him is significantly more than 50 percent.

A random sample of 100 students was taken. Fifty-five of them favored Mike.

Let p = proportion of the students who are in favor of Mike.

So, Null Hypothesis, $H_0$ : p $\leq$ 50% {means that the proportion of student body in favor of him is significantly less than or equal to 50%}

Alternate Hypothesis, $H_A$ : p > 50% {means that the proportion of student body in favor of him is significantly more than 50%}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students body in favor of Mike = $\frac{55}{100}$ = 0.55

n = sample of students taken = 100

So, test statistics = $\frac{0.55-0.50}{\sqrt{\frac{0.55(1-0.55)}{100} } }$

= 1.01

The value of z test statistics is 1.01.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is less than the critical value of z as 1.01 < 1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the proportion of student body in favor of him is significantly less than or equal to 50% or proportion of the students in favor of Mike is not significantly greater than 50 percent.

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3 years ago

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Answer:

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3 years ago

Find the angles of a parallelogram in which an exterior angle is one-third that its interior angle.

iogann1982 [59]

Answer:

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