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Umnica [9.8K]
3 years ago
8

James, Aimee and Zack have

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
3 0

Answer:

29Kg

Step-by-step explanation:

P1=2Kg

P2=7Kg

P3=31Kg

P3-P1=29Kg

To find P1, P2 and P3 I started assigning the first prime number, 2, to P1 and tried to assign prime numbers to P2 and P3 so that the sum was 40, increasing them at each step.

I was lucky and I got the result after few steps :-)

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According to exponent rules, when we multiply two power with the same base we _______ the exponents. Example: c^6⋅ c^4
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Answer:

Step-by-step explanation:

According to exponent rules, when we multiply two power with the same base we<u> </u><u>ADD</u> the exponents.

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3 years ago
The base of a solid is the region in the first quadrant bounded by the line x=-2y+6 and the coordinate axes. What is the volume
nika2105 [10]

Answer:

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V= \frac{4(3)^3}{3} -12(3)^2 +36 (3) -0 = 36-108+108= 36

Step-by-step explanation:

For this case we have the following plot on the figure attached.

We know on this case that x = -2y+6 represent our radius for the square, since we need cross sections perpendicular to the y axis.

We find the intersection points like this:

x= 0 , y=3

y=0, x=6

Since we are assuming squares for the cross sections the area is given by A = r^2 where r = x= -2y+6.

Since our radius is on terms of x we can create a integral with limits on x in order to find the volume, And we can use the following integral in order to find the volume.

V = \int_{0}^3 (-2y+6)^2 = \int_{0}^3 4y^2 -24y +36 dy

On the left part we are using the following property from algebra:

(a+b)^2 = a^2 +2ab +b^2

(-2y+6)^2 = (-2y)^2 +2*(-2y)(6) +(6)^2 = 4y^2 -24y+36

And after do the integral we got this:

V = \frac{4y^3}{3} -12y^2 +36 y \Big|_0^3

V= \frac{4(3)^3}{3} -12(3)^2 +36 (3) -0 = 36-108+108= 36

7 0
3 years ago
32=2 to the what power
Andrew [12]
This question also translates to: How many times do you multiply 2 times itself to get 32? The answer is 5 because you multiply 2 times itself 5 times to get 32.
3 0
4 years ago
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