All categories

3 years ago

C=Wtc/1000 for W please I need help it's algebra

Mathematics

1 answer:

DedPeter [7]3 years ago

3 0

C1000÷ct=w

you pretty much ×1000 and then ÷t and c

You might be interested in

Bert is planning to open a savings account that earns 1.6% simple interest yearly. He wants to earn exactly $240 in interest aft

RoseWind [281]

Answer:

D. $5,000

Step-by-step explanation:

The amount of money he should deposit is the principal.

The principal P can be gotten by

P = 100 I /RT

Where

I = interest

R = rate

T = Time

Given

I = $240

R = 1.6%

T = 3 yrs

P = 100 x 240 /1.6 x 3

Multiply through

= 24000/4.8

= $5000

5 0

3 years ago

Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur

Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

The complete question in English is

You're the commander of a spaceship. Your mission is to reach Alpha Centaur in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel at the speed of light. You know that light can travel a distance of 5.88 x 10^12 miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

$9.3*10^7\ miles$

The spaceship can travel at the speed of light

The light can travel a distance of $5.88*10^{12}\ miles$ in a year

using a proportion

$\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years$

This time is very small in years

Convert to minutes

$1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min$

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

$2.5*10^{13}\ miles$

The spaceship can travel at the speed of light

The light can travel a distance of $5.88*10^{12}\ miles$ in a year

using a proportion

$\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years$

$4.25\ years< 5\ years$

therefore

The spaceship will get to Alpha Centaur in time

3 0

3 years ago

What is the sum of 4/10 + 55/100

neonofarm [45]

4/10 = 40/100

40/100 + 55/100 = 95/100

95/100 is your answer

simplest form: 19/20

hope this helps

4 0

3 years ago

Read 2 more answers

2 + 3 + 8 + 1 + 9 + 10 - 11 +10 = ?

Illusion [34]

The answer is 32 ………………..

7 0

3 years ago

Read 2 more answers

What is the solution of the system? Use elimination. 3x - 4y = 9 -3x + 2y = 9

densk [106]

You add two equations together to eliminate a variable. This particular problem is nice, because it's already setup to eliminate X.

3x - 4y = 9
-3x + 2y = 9

When we add these two together, 3x - 3x cancels each other out, leaving us with 0x, or nothing.

We continue with -4y + 2y (leaves us with -2y) and 9+9 (18).

-2y = 18

18/-2 = -9.

Now we have y = -9, and we can go back into the problems to solve for x.

3x - 4(-9) = 9

3x + 36 = 9.

3x = -27

x = -9.

Confirm with the final equation:

-3(-9) + 2(-9) = 9
27 - 18 = 9
9 = 9 --- Confirmed.

6 0

4 years ago

Read 2 more answers