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Ugo [173]
3 years ago
8

The seventh-grade class earned 40% of the selling price of each flower. In September, they sold 900 flowers. In October, they so

ld 700 flowers. Select a choice from each drop-down menu to make a true statement.
The seventh-grade class earned more money in September or October by $30 or $75 or $190
Mathematics
2 answers:
igor_vitrenko [27]3 years ago
6 0

Answer:

They earned more money in September by $30 dollars

Step-by-step explanation:

The selling price of each flower is .375 dollars per flower, so if they sold 200 more, and the class earns 40% of the selling point we jut have to make the multiplications to know how much they earned for each flower:

.375x.40=.150

No we just multiply that by the difference in the number of flowers sold:

.150x200= 30

And the answer is that they earned $30 more in september than in october.

hjlf3 years ago
3 0
They sold more in September... and they earned more by 30 dollars. Hows flvs? lol
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3 years ago
If you roll two six-faced dice together, you will get 36 possible outcomes. 4 pts 1. List all possible outcomes of the experimen
bezimeni [28]

Given:

Two dice are rolled together.

Total number of possible outcomes.

To find:

The list of total possible outcomes.

The probability of getting a sum of 11 in these outcomes.

The probability of getting a sum less than or equal to 4.

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Solution:

If two dice are rolled together, then the total number of possible outcomes is 36 and list of total possible outcomes is

S = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

Sum of 11 in these outcomes = {(5,6),(6,5),(6,6)} = 3

The probability of getting a sum of 11 in these outcomes is

P(\text{sum=11})=\dfrac{3}{36}

P(\text{sum=11})=\dfrac{1}{12}

Therefore, the probability of getting a sum of 11 in these outcomes is \dfrac{1}{12}.

Sum less than or equal to 4 = {(1,1),(1,2),(1,3),(2,1),(2,2),(3,1)} = 6

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P({sum\leq 4})=\dfrac{6}{36}

P({sum\leq 4})=\dfrac{1}{6}

Therefore, the probability of getting a sum less than or equal to 4 is \dfrac{1}{6}.

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The probability of getting a sum of 13 or more is

P(sum\geq 13)=\dfrac{0}{36}

P({sum\geq 13})=0

Therefore, the probability of getting a sum of 13 or more is 0.

8 0
2 years ago
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tiny-mole [99]

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iogann1982 [59]
Hey There!

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