#1 : ( 3 , - 2 )
~~
#2 : ( - 1 , 4 )
~~
I hope that helps you out!!
Any more questions, please feel free to ask me and I will gladly help you out!!
~Zoey
Mid-segment and bottom side of the triangle is always parallel to each other, and parallel lines must have same slopes, so if their slopes are equal, then MN would be mid-segment of side AB in Triangle ABC
Hope this helps!
Answer:
The proof is below
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of a parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of a parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE
Answer:
x > -11
Step-by-step explanation:
Step 1: Write inequality
x + 3 > -8
Step 2: Solve for <em>x</em>
- Subtract 3 on both sides: x > -11
Here, the inequality is saying that any number greater than -11 will work as a solution.
The number of cats is 2.5 times the number of dogs.
