Answer:
Step-by-step explanation:
Let the number of cockles be c and that of winkles be w.
From the first relation,
w = 2c ..........(I)
From the second relation, 6 winkles are accidentally split.
This in equation form means the following:
c/w- 6 = 3/5
By cross multiplication,
5c = 3(w - 6)...........(ii)
We know w = 2c , let’s substitute this into the second equation.
5c = 3(2c - 6)
5c = 6c - 18
Collecting like times, c = 18
And w = 2c = 2(18) = 36
Hence, there were initially 18 cockles and 36 winkles
Answer:
301.189
Step-by-step explanation:
Given the table :
Source of Variation - - SS - - - df - - - MS - - - - F
Regression - - - - - -3177.17 - - -2 - - 1588.6
Residual - - - - - - - - ______ --17 - - -17.717
Total - - - - - - - - - - 3478.36 - - 19
Calculate the SSR, Sum of Square residual
The Sum of Square RESIDUAL (SSR), Mean Square Residual (MSR) and Degree of Freedom RESIDUAL (DFR) are related by the formular :
MSR = SSR / DFR
Hence,
SSR = MSR × DFR
Fr the table ;
MSR = 17.717 ; DFR = 17
SSR = (17.717 × 17)
SSR = 301.189
Answer:
76%
Step-by-step explanation:
In order to find the answer to this question you must divide the output of dividing 42 and 32 by 100 to receive the answer.
42/32
42/32=1.3125
100=1.3125*x
100/1.3125=x
76.1904761905=x
x=76.1904761905
Hope this helps.
Answer:
15,008 grams
Step-by-step explanation:
You have 30,016 grams of radioactive kind of rubidium. How much will be left after 54 minutes if its half-life is 18 minutes? 15,008 grams.
Answer:
25m−10 would be the answer
