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3 years ago

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Mathematics

2 answers:

miskamm [114]3 years ago

4 0

X=10
3(10)+46=76
14+76=90.

Gre4nikov [31]3 years ago

3 0

Answer:

The answer is 10

Step-by-step explanation:

Because 10 times 3 is 30. and 30 +46 is 76. Then you add 14 and that gets you 90 degrees

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The Wellbuilt Company produces two types of wood chippers, economy and deluxe. The deluxe model requires 3 hours to assemble and

seropon [69]

Answer:

The maximum profit is reached with 4 deluxe units and 6 economy units.

Step-by-step explanation:

This is a linear programming problem.

We have to optimize a function (maximize profits). This function is given by:

$P=98D+72E$

being D: number of deluxe units, and E: number of economy units.

The restrictions are:

- Assembly hours: $3D+2E\leq24$

- Paint hours: $0.5D+1E\leq8$

Also, both quantities have to be positive:

$D\geq 0\\\\E\geq0$

We can solve graphically, but we can evaluate the points (D,E) where 2 or more restrictions are saturated (we know that one of this points we will have the maximum profit)

$(8;0) \rightarrow P=98*8+72*0= 784\\\\(0;8) \rightarrow P= 98*0+72*8=576\\\\(4;6) \rightarrow P=98*4+72*6=824$

The maximum profit is reached with 4 deluxe units and 6 economy units.

4 0

3 years ago

Solve log (4x+5)=2. Round to the nearest thousandth if necessary.

Eva8 [605]

10%5E2+=+4x+%2B+5
100+=+4x+%2B+5
4x+=+95
x+=+23.75
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7 0

4 years ago

Read 2 more answers

45°30' is equal to….

Schach [20]

Answer:

163800"

Step-by-step explanation:

1°=60'

1' =60"

so,

45°30'

=(45°×60×60)"+(30×60)"

=162000"+1800"

=163800"

So,45°30' is equal to 163800".

5 0

3 years ago

The difference of a number and 4 is equal to that same<br> number squared

son4ous [18]

Answer:

16 answer

Step-by-step explanation:

I hope it help

8 0

4 years ago

A large operator of timeshare complexes requires anyone interested in making a purchase to first visit the site of interest. His

morpeh [17]

Answer:

There is a 21.053% probability that this person made a day visit.

There is a 39.474% probability that this person made a one night visit.

There is a 39.474% probability that this person made a two night visit.

Step-by-step explanation:

We have these following percentages

20% select a day visit

50% select a one-night visit

30% select a two-night visit

40% of the day visitors make a purchase

30% of one night visitors make a purchase

50% of two night visitors make a purchase

The first step to solve this problem is finding the probability that a randomly selected visitor makes a purchase. So:

$P = 0.2(0.4) + 0.5(0.3) + 0.3(0.5) = 0.38$

There is a 38% probability that a randomly selected visitor makes a purchase.

Now, as for the questions, we can formulate them as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

Suppose a visitor is randomly selected and is found to have made a purchase.

How likely is it that this person made a day visit?

What is the probability that this person made a day visit, given that she made a purchase?

P(B) is the probability that the person made a day visit. So $P(B) = 0.20$

P(A/B) is the probability that the person who made a day visit made a purchase. So $P(A/B) = 0.4$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.4*0.2}{0.38} = 0.21053$

There is a 21.053% probability that this person made a day visit.

How likely is it that this person made a one-night visit?

What is the probability that this person made a one night visit, given that she made a purchase?

P(B) is the probability that the person made a one night visit. So $P(B) = 0.50$

P(A/B) is the probability that the person who made a one night visit made a purchase. So $P(A/B) = 0.3$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.3}{0.38} = 0.39474$

There is a 39.474% probability that this person made a one night visit.

How likely is it that this person made a two-night visit?

What is the probability that this person made a two night visit, given that she made a purchase?

P(B) is the probability that the person made a two night visit. So $P(B) = 0.30$

P(A/B) is the probability that the person who made a two night visit made a purchase. So $P(A/B) = 0.5$

P(A) is the probability that the person made a purchase. So $P(A) = 0.38$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.5}{0.38} = 0.39474$

There is a 39.474% probability that this person made a two night visit.

3 0

4 years ago