F(2)= 4(16) - 6(4) + 8(2) - 15
F(2)= 64 -24 + 16 - 15
F(2)= 41
Answer:



Step-by-step explanation:
Given



(0, 1, 0)
The vector equation is given as:

Substitute values for x, y and z

Differentiate:

The parametric value that corresponds to (0, 1, 0) is:

Substitute 0 for t in r'(t)




The tangent line passes through (0, 1, 0) and the tangent line is parallel to r'(0)
It should be noted that:
The equation of a line through position vector a and parallel to vector v is given as:

Such that:
and 
The equation becomes:




By comparison:
and 
The parametric equations for the tangent line are:



Hello,
H^(-1)(x)=-3/2 x+9
Answer A
Indeed:
y=-2/3x+6-->x=-2/3 y +6 ==>3x=-2y+18==>2y=-3x+18==>y=-3/2 x +9