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3 years ago

In circle T, PTQ = RTS.What is the length of PQ?3 units4 units6 units7 units

Mathematics

2 answers:

kupik [55]3 years ago

5 0

Answer:

4 units

Step-by-step explanation:

telo118 [61]3 years ago

3 0

Answer:

4 units

Step-by-step explanation:

The picture of the question in the attached figure

we know that

Triangle PTQ≅Triangle RTS

Remember that

If two figures are congruent, then its corresponding sides and the corresponding angles are congruent

PQ≅RS

we have

$RS=4\ units$

therefore

$PQ=4\ units$

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In the given figure, O is the centre of a circle, TN is a Tangent, AN = 12 cm and OE = 5 cm. Find the length of NE.

sp2606 [1]

Answer:

NE = 8 cm

Step-by-step explanation:

Radius OA = OE = 5 cm

In right triangle OAN, OA² + AN² = ON²

5² + 12² = ON²

ON² = 25 + 144 = 169

so ON = 13 cm

NE = ON - OE = 13 - 5 = 8 cm

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2 years ago

Find the sum of 6x2 + 10x – 1 and -5x2 – 2x + 1.

Stolb23 [73]

Answer:

x2+8x

Step-by-step explanation:

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3 years ago

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A+3b = 7, c= 3 , then the value of a+3 (b+c ) =............

vaieri [72.5K]

Answer:

Step-by-step explanation:

a+ 3(b + c)

a + 3b + 3c

but a + 3b = 7 and c = 3

7+3(3)

7 + 9

=16

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2 years ago

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Identify the number of solutions of the system of linear equations. 5x+y−z=6 x+y+z=2 12x+4y=10

asambeis [7]

Answer:

x = $\frac{19}{12}$ y = $(-\frac{9}{4} )$ z = $\frac{8}{3}$ One solution for each variable.

Step-by-step explanation:

5x + y − z = 6

x + y + z = 2

12x + 4y = 10

The first thing we need to do is solve for x in the 3rd equation because it inly have 2 variables, x and y.

12x + 4y = 10 Subtract 4y from each side

12x + 4y - 4y = 10 - 4y

12x = 10 - 4y Pull 2 out on the right side

12x = 2(5 - 2y) Divide each side by 12

12x/12 = 2(5 - 2y)/12

x = 2(5 - 2y)/12

x = (5 - 2y)/6

Now we plug in our x value into the 2nd equation and solve for z

x + y + z = 2

$\frac{5-2y}{6}$ + y + z = 2 Multiply each side by 6

6( $\frac{5-2y}{6}$ + y + z) = 2 * 6

6( $\frac{5-2y}{6}$ + y + z) = 12

5 - 2y + 6y + 6z = 12 Combine like terms

5 + 4y + 6z = 12 Subtract 5 from each side

5 - 5 + 4y + 6z = 12 - 5

4y + 6z = 7 Subtract 4y from each side

4y - 4y + 6z = 7 - 4y

6z = 7 - 4y Divide each side by 6

6z/6 = (7 - 4y)/6

z = (7 - 4y)/6

Now we solved for z and x, so in the 1st equation we plug in x and z.

5x + y − z = 6

5( $\frac{5-2y}{6}$ ) + y - $\frac{7-4y}{6}$ = 6 Multiply each side by 6

6*(5( $\frac{5-2y}{6}$ ) ) + 6y - 6( $\frac{7-4y}{6}$ ) = 6*6

6*(5( $\frac{5-2y}{6}$ ) ) + 6y - 6( $\frac{7-4y}{6}$ ) = 36

5(5 - 2y) + 6y - 7 - 4y = 36

25 - 10y + 6y - 7 - 4y = 36 Rearrange to make it easier to combine terms.

25 - 7 - 10y + 6y - 4y = 36

18 - 8y = 36 Subtract 18 from each side.

18 - 18 - 8y = 36 - 18

- 8y = 36 - 18

- 8y = 18 Divide each side by -8

- 8y/-8 = 18/- 8

y = 18/- 8

y = - 9/4

Now we plug our answer for y back into the 3rd equation and solve for the value of x.

12x + 4y = 10

12x + 4 $(-\frac{9}{4} )$ = 10

12x - 9 = 10 Add 9 to each side

12x - 9 + 9 = 10 + 9

12x = 10 + 9

12x = 19 Divide each side by 12

12x/12 = 19/12

x = 19/12

Now we have a value for x and y so plug these into the 2nd equation to sovle for z.

x + y + z = 2

$\frac{19}{12}$ + $(-\frac{9}{4} )$ + z = 2 We need to find the common denominator in order to add.

$(-\frac{9}{4} )$ * $\frac{3}{3}$ = $-\frac{27}{12}$

$\frac{19}{12}$ $-\frac{27}{12}$ + z = 2

$-\frac{8}{12}$ + z = 2 Add $-\frac{8}{12}$ to each side

$-\frac{8}{12}$ $+ \frac{8}{12}$ + z = 2 $+ \frac{8}{12}$

z = 2 $+ \frac{8}{12}$ Reduce $+ \frac{8}{12}$ to $\frac{2}{3}$

z = 2 + $\frac{2}{3}$ To add find a common denominator.

$2 * \frac{3}{3} = \frac{6}{3}$

z = $\frac{6}{3}$ + $\frac{2}{3}$

z = $\frac{8}{3}$

So there is 1 solution for each variable.

8 0

3 years ago

Use the drawing tool(s) to form the correct answer on the provided graph. The function f(x) is shown on the provided graph. Grap

MariettaO [177]

Answer:

$f(x)=x+6 \\$

Step-by-step explanation:

The transformation is a translation 6 units up.

$f(x)=x+6 \\$

We can use the parent function f(x)=x, which is a linear function to graph this function.

Then just translate the function 6 units up.

6 0

3 years ago

In circle T, PTQ = RTS.What is the length of PQ?3 units4 units6 units7 units​

In circle T, PTQ = RTS.What is the length of PQ?3 units4 units6 units7 units