You have two angles congruent, plus a side that's NOT between them.
I guess you'd call that situation " AAS " for "angle-angle-side".
That's what you have, and it's NOT enough to prove the triangles
congruent. There can be many many different pairs of triangles
that have AAS = AAS.
So there's no congruence postulate to cover this case, because they're
not necessarily.
Answer: The first one, the last one,
Step-by-step explanation:
Answer:
24,192.
Step-by-step explanation:
The first number must be one of 2,3,4,5,6,7,8 or 9. That is 8 possibilities.
The number of permutations of the other 4 numbers is 9P4
= 9! / (9-4)!
= 3024
Now we multiply by the 8:
3024 * 8
= 24,192.
Answer:
i think a
Step-by-step explanation:
i'm not sure
Answer:
(1.13, 7.74) and (-4.13, 18.26)
Step-by-step explanation:
This can be solved in two ways: mathematically and graphically.
<u>Graphing</u>
Plot both lines and find where they intersect. See the attachment.
The intersection points are (1.13, 7.74) and (-4.13, 18.26)
<u>Mathematical</u>
y + 2x = 10
y = 10 - 2x
y = 3x² + 7x - 4
10 - 2x = 3x² + 7x - 4
3x² + 9x - 14 = 0
Solve this using the quadratic equation:
x = 1.13 and -4.13
Use these two values of x to find y:
y = 10 - 2x
y = 10 - 2(1.13)
y = 7.74
y = 10 -2x
y = 10 -2(-4.13)
y = 18.26
The two points are:
(1.13, 7.74) and (-4.13, 18.26)