<span>Consider the triangles ERT and CTR.
|ER|=|CT| shown
(</span>Therefore, one can say that segment ER is congruent to segment CT.)
m(R)=m(T)= 90°shown
(By the definition of a rectangle, all four angles measure 90°)
|RT|=|TR|
so we have Side Angle Side congruence.
By the <span>(SAS) Theorem, the triangles are congruent.
Answer: </span><span>C (SAS) Theorem</span>
Step-by-step explanation:
Probability that Dan chooses a Green card = 0.2
Probability that Esther chooses a Green card = 0.2 (same set of cards = same probability)
Since they are independent events,
total probability = 0.2 * 0.2 = 0.04.
Answer:
Step-by-step explanation:
I think you have the question incomplete, and that this is the complete question
sin^4a + cos^4a = 1 - 2sin^2a.cos^2a
To do this, we can start my mirroring the equation.
x² + y² = (x + y)² - 2xy,
This helps us break down the power from 4 to 2, so that we have
(sin²a)² + (cos²a)² = (sin²a + cos²a) ² - 2(sin²a) (cos²a)
Recall from identity that
Sin²Φ + cos²Φ = 1, so therefore
(sin²a)² + (cos²a)² = 1² - 2(sin²a) (cos²a)
On expanding the power and the brackets, we find that we have the equation proved.
sin^4a + cos^4a = 1 - 2sin^2a.cos^2a
Which polynomial is equal to (-3x^2 + 2x - 3) subtracted from (x^3 - x^2 + 3x)?
<h3><u><em>
Answer:</em></u></h3>
The polynomial equal to (-3x^2 + 2x - 3) subtracted from (x^3 - x^2 + 3x) is 
<h3><u><em>Solution:</em></u></h3>
Given that two polynomials are: 
and 
We have to find the result when is subtracted from
In basic arithmetic operations,
when "a" is subtracted from "b" , the result is b - a
Similarly,
When is subtracted from , the result is:
Let us solve the above expression
<em><u>There are two simple rules to remember: </u></em>
- When you multiply a negative number by a positive number then the product is always negative.
- When you multiply two negative numbers or two positive numbers then the product is always positive.
So the above expression becomes:
Removing the brackets we get,
Combining the like terms,
Thus the resulting polynomial is found
