
Step-by-step explanation:
Hello, please consider the following.
Using Maclaurin series expansion, we can find an equivalent of sin(x) in the neighbourhood of 0.

Then,

Thank you
-2x = -1
x = 1/2
Any equation that returns x=1/2 is a solution to this problem. For example, x= (3•4)/6 can be simplified so that x=1/2
Answer:
True
Step-by-step explanation:
Answer: 1/729
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