X(x + 2) = 120sq units
<span>Set it equal to 0 </span>
<span>x^2 + 2x - 120 = 0 </span>
<span>factor </span>
<span>(x + 12)(x - 10) </span>
<span>For the shorter side: </span>
<span>x - 10 = 0 </span>
<span>x = 10 </span>
<span>Now that you have x, solve for the longer side which we said was represented by </span>
<span>x + 2 </span>
<span>10 + 2 = 12 </span>
<span>Proof </span>
<span>A = L x W </span>
<span>120 = 10 x 12 </span>
<span>120 = 120 </span>
<span>true </span>
<span>Our length is 12 and our width is 10</span>
4.5x - 9.5 > 62.5
4.5x > 62.5 + 9.5
4.5x > 72
x > 72/4.5
x > 16 <==
Answer:Rs15
Step-by-step explanation:
150g=150/1000=0.15kg
1kg cost Rs100
0.15kg cost =100 x 0.15=15
150g cost Rs15
Answer:
Third
Step-by-step explanation:
Acceleration is the rate of change of the rate of change of position
In the third, the rate of change is negative, and the rate of change of that is decreasing as time passes.
Answer:
Tn = 2Tn-1 - Tn-2
Step-by-step explanation:
Before we can generate the recursive sequence, we need to find the nth term of the given sequence.
nth term of an AP is given as:
Tn = a+(n-1)d
If a17 = -40
T17 = a+(17-1)d = -40
a+16d = -40 ...(1)
If a28 = -73
T28 = a+(28-1)d = -73
a+27d = -73 ...(2)
Solving both equations simultaneously using elimination method.
Subtracting 1 from 2 we have:
27d - 16d = -73-(-40)
11d = -73+40
11d = -33
d = -3
Substituting d = -3 into 1
a+16(-3) = -40
a - 48 = -40
a = -40+48
a = 8
Given a = 8, d = -3, the nth term of the sequence will be
Tn = 8+(n-1) (-3)
Tn = 8+(-3n+3)
Tn = 8-3n+3
Tn = 11-3n
Given Tn = 11-3n and d = -3
Tn-1 = Tn - d... (3)
Tn-1 = 11-3n +3
Tn-1 = 14-3n
Tn-2 = Tn-2d...(4)
Tn-2 = 11-3n-2(-3)
Tn-2 = 11-3n+6
Tn-2 = 17-3n
From 3, d = Tn - Tn-1
From 4, d = (Tn - Tn-2)/2
Equating both common difference
(Tn - Tn-2)/2 = Tn - Tn-1
Tn - Tn-2 = 2(Tn - Tn-1)
Tn - Tn-2 = 2Tn-2Tn-1
2Tn-Tn = 2Tn-1 - Tn-2
Tn = 2Tn-1 - Tn-2
The recursive formula will be
Tn = 2Tn-1 - Tn-2