Answer:
The value of Car B will become greater than the value of car A during the fifth year.
Step-by-step explanation:
Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.
In the attached excel file, the following are used:
Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000
Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000
Annual Depreciation expense of Car B in Year 7 = Beginning value of Car B in Year 7 = 2,000
Conclusion
Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.
Answer:
here is a multiplication scale
Step-by-step explanation:
Answer:
13/14 is greater
Step-by-step explanation:
Find the lcm for both:
<u>9 x 7 </u> = <u>63</u>
10 x 7 70
<u>13 x 5 </u> = <u>65</u>
14 x 5 70
so therefore 13/14 is greater since it has a greater value when finding the lcm
Answer:
1,757,600
Step-by-step explanation:
26x26x26x10x10 = 1,757,600
Answer:
12x +14
1.) divide both sides but 12 to get the variable alone
12x becomes just the variable x
14 is now 1.16 with the 6 having a line above it showing its repeating.
x = 1.16 repeated