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The correct slope of the line that passes through the points (1,-3) and (3,-5)

ehidna [41]

(1,-3)(3,-5)
slope = (-5 - (-3) / (3 - 1) = (-5 + 3) / 2 = -2/2 = -1 <==

7 0

2 years ago

Read 2 more answers

What is the solution of x=2+√x-2 ?

Blizzard [7]

C. \: x = 2 \: or \: x = 3

3 0

3 years ago

A box of granola bars contains 3 chocolate chip bars, 2 peanut butter bars, 1 lemon bar, and 4 raisin bars. Iesha will randomly

ella [17]

Answer:

2/45

Step-by-step explanation:

Note this selection is done without replacement hence after each selection sample size will reduce

Given data

Samples 3 chocolate chip bars,

2 peanut butter bars,

1 lemon bar, and

4 raisin bars

Sample size S= [3+2+1+4]= 10

Probability that first selection is lemon = 1/10

Probability that second selection is raisin = 4/9

Hence the probability that the first bar Iesha selects will be lemon and the second will be raisin= 1/10*4/9

= 4/90= 2/45

3 0

2 years ago

Find the measure of the arc or angle indicated

MariettaO [177]

Short Answer: arc LM = 110°
Comment
Any two angles that have their end points on the same end points as a chord and both moving away in the same direction (in this case down ) are equal. This is a fundamental fact about circles.

Equation
2x + 55 = x + 55
the only way this is going to make any sense is if x = 0. No other value is possible because it will destroy the equality.

Conclusion
Both angles = 55

But that's not what you are asked for.

What you are asked for
You want to know the measure of arc LM.
The angle connecting the center of the circle with its two arms running through the end points of the chord = the measure of arc LM

Draw a dot where the center of the circle is and call it O. Draw in <MOL
<MOL = 2* either of the 55° = 2 (<LKM) = 2 * 55 = 110° That's a property of the central angle.

The measure of arc LM = 110°

6 0

3 years ago

⊙O and ⊙P are given with centers (−2, 7) and (12, −1) and radii of lengths 5 and 12, respectively. Using similarity transformati

goldenfox [79]

Answer:

Whereby circle $\bigodot$ P can be obtained from circle $\bigodot$ O by applying the transformations of a translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, $\bigodot$ O is similar to $\bigodot$ P

Step-by-step explanation:

The given center of the circle $\bigodot$ O = (-2, 7)

The radius of $\bigodot$ O, r₁ = 5

The given center of the circle $\bigodot$ P = (12, -1)

The radius of $\bigodot$ P, r₂ = 12

The similarity transformation to prove that $\bigodot$ O and $\bigodot$ P are similar are;

a) Move circle $\bigodot$ O 14 units to the right and 8 units down to the point (12, -1)

b) Apply a scale of S.F. = r₂/r₁ = 12/5 = 2.4

Therefore, the radius of circle $\bigodot$ O is increased by 2.4

We then obtain $\bigodot$ O' with center at (12, -1) and radius r₃ = 2.4×5 = 12 which has the same center and radius as circle $\bigodot$ P

∴ Circle $\bigodot$ P can be obtained from circle $\bigodot$ O by applying similarity transformation of translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, $\bigodot$ O is similar to $\bigodot$ P.

7 0

3 years ago