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ki77a [65]
3 years ago
6

NEED ANSWER ASAP According to Ohm’s law, resistance is equal to voltage divided by

Chemistry
1 answer:
boyakko [2]3 years ago
8 0

Answer:

A

Explanation:

Ohm's law is stated as E = current * resistance (E = I * R)

When you rearrange the formula, you get R = E/I

The answer is current -- A

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4 0
3 years ago
Identify each of the following reactions as balanced or unbalanced. CH4+ 2O2 → CO2 + 2H2O: CaCl2+ 2AgNO3 → Ca(NO3)2 + 2AgCl: 3Fe
kap26 [50]

1) The answer is: chemical reaction is balanced.

Chemical reaction: CH₄ + O₂ → CO₂ + H₂O.

Oxidation reaction: C⁻⁴ → C⁺⁴ + 8e⁻.

Reduction reaction: O₂ + 4e⁻ → 2O⁻² /×2; 2O₂ + 8e⁻ → 4O⁻².

Balanced chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.

Carbon change oxidation number from -4 to +4 (oxidation) and oxygen change oxidation number from 0 to -2 (reduction).

2) The answer is: chemical reaction is balanced.

Balanced chemical reaction: CaCl₂ + 2AgNO₃ → Ca(NO₃)₂ + 2AgCl.

Number of atoms must be the same on left and right side of balanced chemical reaction according to the law of conservation of mass or principle of mass conservation.

There are two chlorine atoms (Cl), one calcium atom (Ca), six oxygen atoms (O), one nitrogen atoms (N) and two silver atoms (Ag) in this balanced chemical reaction.

3) The answer is: chemical reaction is unbalanced.

Chemical reaction: 3Fe₃O₄ + 4Al → 9Fe + 4Al₂O₃.

Number of aluminium atoms (Al) is unbalanced. There are four aluminium atoms on the left and eight aluminium atoms on right side of chemical reaction.

Balanced chemical reaction: 3Fe₃O₄ + 8Al → 9Fe + 4Al₂O₃.

According to principle of mass conservation, number of atoms must be equal on both side of chemical reaction.

8 0
3 years ago
Read 2 more answers
How many moles of each element are in one mole of Sr(HCO3)2?
Alla [95]
Sr = 1 mol
H = C = 2 mol each
O = 6 mol
7 0
3 years ago
Read 2 more answers
Determine the number of miles of C in each sample​
stiv31 [10]
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6 0
3 years ago
What amount of ice must be added to 250 g of water at 15°c to cool the water to 0°c and have no ice left
Juliette [100K]

Answer:

\mathbf{m= 47 \ g}

Explanation:

The heat needed to melt ice (q_1) + heat needed to cool water (q_2) = 0

m\Delta H_{fusion} + mc \Delta T = 0

m \times 333.55 J g^{-1} + 250 \ g \times 4.184 \ Jg^{-1 \ 0 } \times (-15.0 \ ^0 C) = 0

m \times 333.55 J g^{-1} =15690

m=\dfrac{15690 \ J }{333.55 J g^{-1} }

\mathbf{m= 47 \ g}

7 0
3 years ago
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