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bekas [8.4K]
3 years ago
13

So, there's this really cute guy. He laughs a moderate amount around me, and I think we click really well. He teaches me when I

need teaching, and he makes me laugh. When we talk, I try to do my best to look nice or something, and my heart beats faster than usual. But, when I think about taking a bullet for him, I don't really think I could take it that far. Is this just a passing fling? Or could it turn into something... I don't know, REAL?
Chemistry
2 answers:
OlgaM077 [116]3 years ago
6 0

you two may go into a relationship. Taking a bullet would be if your strongly in love with someone. engaged marriage kind of love in my opinion. This could also just be a crush and maybe one day your not interested in this guy anymore and/or didnt end up going in a relationship. Good luck if things work with this guy or not :)


-Wolfs c:

a_sh-v [17]3 years ago
5 0
Love is a powerful thing i advice you not to put your all in him take it slow a be careful
You might be interested in
Measuring levels of pollutants, such as nitrogen oxide in the atmosphere, is an example of chemistry research that ____.
Paraphin [41]

Answer:

aims to benefit the environment is the correct answer.

Explanation:

The goal of Aims to the benefits environment is to provide everyone information, values, and skills which are required to preserve and protect the environment.

Aims to benefit the environment includes

  • To decrease emissions and reduce pollution.
  • To improve waste management methods.
  • To reduce the consumption of natural sources.
  • To minimize noise and different nuisances.

3 0
3 years ago
Consider the reaction below for which K = 78.2 atm-1. A(g) + B(g) ↔ C(g) Assume that 0.386 mol C(g) is placed in the cylinder re
borishaifa [10]

Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

                        A            +            B           ⇄        C

where;

numbers of moles = 0.386 mol C  (g)

Volume =  7.29 L

Molar concentration of C = \frac{0.386}{7.29}

= 0.053 M

                        A            +            B           ⇄        C

Initial               0                           0                      0.530    

Change          +x                          +x                       - x

Equilibrium      x                           x                      (0.0530 - x)

K = \frac{[C]}{[A][B]}

where

K is given as ; 78.2 atm-1.

So, we have:

78.2=\frac{[0.0530-x]}{[x][x]}

78.2= \frac{(0.0530-x)}{(x^2)}

78.2x^2= 0.0530-x

78.2x^2+x-0.0530=0  

Using quadratic formula;

\frac{-b+/-\sqrt{b^2-4ac} }{2a}

where; a = 78.2 ; b = 1 ; c= - 0.0530

= \frac{-b+\sqrt{b^2-4ac} }{2a}   or \frac{-b-\sqrt{b^2-4ac} }{2a}

= \frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}  or \frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}

= 0.0204  or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

     = 0.0530 - 0.0204

     = 0.0326

Total number of moles at equilibrium = 0.0204 +  0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

V = \frac{nRT}{P}

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K  (fixed constant temperature )

V (volume) = ???

V=\frac{(0.0734*0.0821*273.15)}{(1.00)}

V = 1.64604

V ≅ 1.65 L

3 0
3 years ago
Balance the following skeleton reaction and identify the oxidizing and reducing agents: Include the states of all reactants and
rusak2 [61]

Answer:

4Zn_(_s_)~+~7OH^-~_(_a_q_)~+~NO_3^-_(_a_q_)~+~6H_2O_(_l_)~-->4Zn(OH)_4^-^2_(_a_q_)~+~NH_3_(_g_)

-) Oxidizing agent: NO_3^-_(_a_q_)

-) Reducing agent: Zn_(_s_)

Explanation:

The first step is separate the reaction into the <u>semireactions</u>:

A.Zn~->Zn(OH)_4^-^2

B.NO_3^-~->~NH_3

If we want to balance in <u>basic medium </u>we have to follow the rules:

1. We adjust the oxygen with OH^-

2. We adjust the H with H_2O

3. We adjust the charge with e^-

Lets balance the first semireaction A. :

Zn~+~4OH^-~->Zn(OH)_4^-^2~+~2e^-

Now, lets balance semireaction B:

NO_3^-~+~8e^-~+~6H_2O~->~NH_3~+~9OH^-

Finally, we have to add the two semireactions:

_________________________________________

8~(Zn~+~4OH^-~->Zn(OH)_4^-^2~+~2e^-)

2~(NO_3^-~+~8e^-~+~6H_2O~->~NH_3~+~9OH^-)

_________________________________________

(8Zn~+~32OH^-~->8Zn(OH)_4^-^2~+~16e^-)

(2NO_3^-~+~16e^-~+~12H_2O~->~2NH_3~+~18OH^-)

Cancel out the species on both sides:

8Zn~+~14OH^-~+~2NO_3^-~+~12H_2O~-->8Zn(OH)_4^-^2~+~2NH_3

Simplifying the equation :

4Zn~+~7OH^-~+~NO_3^-~+~6H_2O~-->4Zn(OH)_4^-^2~+~NH_3

The Zn_(_s_) is <u>oxidized</u> therefefore is the <u>reducing agent</u>. The NO_3^-_(_a_q_)is<u> reduced</u> therefore is the <u>oxidizing agent</u>.

4 0
4 years ago
The accepted value for the density of iron is 7.9 g/mL. Four student groups examine the density of iron in the lab. Which of the
nalin [4]

For 5.43 g/mL and 5.44 g/mL =  0.01 the least diff and most precise.

First of all, precision is determined by the difference in the two obtained values. If the difference between the two values obtained is less, then precision is more. If the difference between the two values obtained is more, then precision is less.

For 5.43 g/mL and 5.44 g/mL , we can see that the difference between these two data is 0.01

For 7.98 g/mL and 7.91 g/mL , we can see that the difference between these two data is 0.07

For 7.65 g/mL and 7.64 g/mL , we can see that the difference between these two data is 0.01

For 7.06 g/mL and 7.03 g/mL , we can see that the difference between these two data is 0.03

As we can see that, the most difference between the data is 0.07 between 7.65 g/mL and 7.64 g/mL and thus, they are least precise.

To know more about precision visit :

brainly.com/question/28336863

#SPJ9

3 0
2 years ago
PLEASE HELP!<br><br>Why is phosphorus diamagnetic.
Tamiku [17]

I can't believe it and phosphorus diamagnetic.

5 0
4 years ago
Read 2 more answers
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