Question

How many grams of solute are needed to order to prepare 100.00 mL of a 0.1000 M solution of a compound with a molecular weight of 350.0 g/mol

Answer 1

The grams of solute are required.

The mass of solute is 3.5 g

c =  Molarity = 0.1 M

M = Molar mass = 350 g/mol

V = Volume of solution = 100 mL = 0.1 L

n = Number of moles

m = Mass of solute

Molarity is given by

$c=\dfrac{n}{V}\\\Rightarrow n=cV\\\Rightarrow n=0.1\times 0.1\\\Rightarrow n=0.01\ \text{moles}$

Molar mass is given by

$M=\dfrac{m}{n}\\\Rightarrow m=Mn\\\Rightarrow m=350\times 0.01\\\Rightarrow m=3.5\ \text{g}$

The mass of solute is 3.5 g

Learn more:

brainly.com/question/16633651?referrer=searchResults

Answer 2

Answer:

i got 35 but i am as lost as you are so don't really take my answer as a trusted answer