Answer:
dA/dt = 31 in²/ sec
Step-by-step explanation:
The area of the triangle is:
A(t) = (1/2)*b*h where b is the base and h the height
Differentiation on both sides of the equation we obtain
dA/dt = (1/2)* db/dt * h + (1/2)* dh/dt * b (1)
db/dt = 3 in/sec
dh/dt = 2 n/sec
b = 10 in
h = 14 in
By substitution in (1)
dA/dt = 0,5* 3*14 + 0,5* 2*10
dA/dt = 21 in² /sec + 10 in²/sc
dA/dt = 31 in²/ sec
Answer:
When you distribute something, you are dividing it into parts. In math, the distributive property helps simplify difficult problems because it breaks down expressions into the sum or difference of two numbers.
Good luck !
Assuming that the inequality you were going for was a ≤, set both polynomials less than or equal to 0.
x - 3 ≤ 0
x + 5 ≤ 0
For the first equation add 3 to both sides of the inequality. For the second, subtract 5 from both sides.
x ≤ 3
x ≤ - 5
These would be your solutions I guess, however, if you want to expand upon that, your actual answer is (- ∞, - 5] because if you were to plot these two inequalities on a number line, that is where the overlap would occur.
I believe in standard form this would be 31/2 + 27i/2
