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Talja [164]
3 years ago
14

How do I find the ratio of this? It makes no sense to me

Mathematics
1 answer:
Volgvan3 years ago
5 0

Answer:

\frac{169}{289}

Step-by-step explanation:

Given 2 similar figures with ratio of sides = a : b, then

ratio of areas = a² : b²

Here ratio of sides = 52 : 68 = 13 : 17 ← in simplest form, thus

ratio of areas = 13² : 17² = 169 : 289 = \frac{169}{289}

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write and equation of the line parallel to the line  2 x + 4 y = 20 2 x + 4 y = 20 and containing the point  ( −
MAXImum [283]

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m represents the slope of the line

c represents the y intercept

The equation of the given line is

2x + 4y = 20

4y = - 2x + 20

Dividing through by 4, it becomes

y = - x/2 + 5

Comparing with the slope intercept form, slope = - 1/2

If two lines are parallel, it means that they have the same slope. Therefore, the slope of the line passing through (- 6, 3) is - 1/2

To determine the y intercept, we would substitute m = - 1/2, x = - 6 and y = 3 into y = mx + c. It becomes

3 = - 1/2 × - 6 + c

3 = 3 + c

c = 3 - 3 = 0

The equation becomes

y = - x/2

4 0
3 years ago
6,657 ÷ 6 = Whats the answer and if there is a remander what is the remander
sdas [7]
The answer is 1,109.5
8 0
3 years ago
Read 2 more answers
Leam with an example
Nata [24]

Answer:

18 because 6 times 2 is twelve and 9 times 2 is 18... only if its direcrly proportional which it is

Step-by-step explanation:

pls mark brainliest it would really help me out

8 0
3 years ago
Find the value of sin(a/2) if cosa= 12/13<br>​
daser333 [38]

Answer: sin\frac{a}{2} = ± \frac{1}{\sqrt{26} }

Step-by-step explanation:

We very well know that,

cos2A=1−2sin²A

⟹ sinA = ±\sqrt{(1-} \frac{cos2A}{2} )

As required,  set A = \frac{a}{2}   &   cos a=  \frac{12}{13}    ,thus we get

sin \frac{a}{2} =± \sqrt{\frac{1-cos a}{2} }  

∴ sin\frac{a}{2} =±\sqrt{\frac{1-\frac{12}{13} }{2} } = ± \frac{1}{\sqrt{26} }

   since ,360° < \frac{a}{2} <450°

             ,180° < \frac{a}{2} <225°

Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.

hope it helped!

   

5 0
3 years ago
-12&lt;-6x please help
pishuonlain [190]
-12 < -6x

-12/-6 > x    divide both sides by -6

12/6 > x      two negatives makes a positive

2 > x            simplify

x < 2           
switch sides

hope this helps, God bless! 
6 0
3 years ago
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