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anyanavicka [17]
2 years ago
8

the perimeter of a pentagon (a five-sided polygon) is 50 in. the five sides are represented by consecutive integers. Find the le

ngths of the side
Mathematics
1 answer:
posledela2 years ago
7 0

Answer:

  8, 9, 10, 11, 12

Step-by-step explanation:

Consecutive integer problems are often easier to work if you consider average values. Here, the middle of the 5 consecutive integers is their average, which is 50/5 = 10.

This tells you the integer side lengths are 8, 9, <em>10</em>, 11, 12.

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Answer:

the difference is that the 2 extra LARGE containers weigh bigger than the

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Step-by-step explanation:

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2 years ago
I need help on these what is 5=g-8
Levart [38]
The answer is g=13 I hope this helped
7 0
3 years ago
Find the difference (20m+3)-(7m-5)
xz_007 [3.2K]

Answer:

Simplifying

(20m + 3) + -1(7m + -5) = 0

Reorder the terms:

(3 + 20m) + -1(7m + -5) = 0

Remove parenthesis around (3 + 20m)

3 + 20m + -1(7m + -5) = 0

Reorder the terms:

3 + 20m + -1(-5 + 7m) = 0

3 + 20m + (-5 * -1 + 7m * -1) = 0

3 + 20m + (5 + -7m) = 0

Reorder the terms:

3 + 5 + 20m + -7m = 0

Combine like terms: 3 + 5 = 8

8 + 20m + -7m = 0

Combine like terms: 20m + -7m = 13m

8 + 13m = 0

Solving

8 + 13m = 0

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-8' to each side of the equation.

8 + -8 + 13m = 0 + -8

Combine like terms: 8 + -8 = 0

0 + 13m = 0 + -8

13m = 0 + -8

Combine like terms: 0 + -8 = -8

13m = -8

Divide each side by '13'.

m = -0.6153846154

Simplifying

m = -0.6153846154Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Log(x-2)+log2=2logy<br>log(x-3y+3)=0​
In-s [12.5K]

Answer:

<h2>x = 4 and y = 2 or x = 10 and y = 4</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right

===========================\\\text{DOMAIN:}\\\\x-2>0\to x>2\\y>0\\x-3y+3>0\to x-3y>-3\\=====================\\\\\text{We know:}\ \log_ab=c\iff a^c=b,\\\\\text{therefore}\ \log_ab=0\iff a^0=b\to b=1\\\\\text{From this we have}\\\\\log(x-3y+3)=0\iff x-3y+3=1\qquad\text{add}\ 3y\ \text{to both sides}\\\\x+3=3y+1\qquad\text{subtract 3 from both isdes}\\\\\boxed{x=3y-2}\qquad(*)\\\\\text{Substitute it to (1)}

\log(3y-2-2)+\log2=2\log(y)\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log(3y-4)+\log2=\log(y^2)\qquad\text{subtract}\ \log(y^2)\ \text{from both sides}\\\\\log(3y-4)+\log2-\log(y^2)=0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log\dfrac{(3y-4)(2)}{y^2}=0\qquad\text{use}\ \log_ab=0\Rightarrow b=1\\\\\dfrac{(3y-4)(2)}{y^2}=1\iff y^2=(3y-4)(2)\\\\\text{Use the distributive property}\ a(b+c)=ab+ac

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\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D

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Gnoma [55]

Answer:

176

Step-by-step explanation:

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5 0
1 year ago
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