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REY [17]
3 years ago
15

Testing app whats y=

Mathematics
1 answer:
bulgar [2K]3 years ago
4 0
Y = 3x + 2

Slope is 3 and y intercept is 2 (given in table with (0,2))
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Answer CORRECTLY !!!!! Will mark brainliest !!!!
mash [69]

Answer:

g(q) = \frac{5q}{8}

Step-by-step explanation:

Given

- 7q + 12r = 3q - 4r

Rearrange making r the subject

Add 7q to both sides

12r = 10q - 4r ( add 4r to both sides )

16r = 10q ( divide both sides by 16 )

r = \frac{10q}{16} = \frac{5q}{8} , thus

g(q) = \frac{5q}{8}

4 0
3 years ago
Read 2 more answers
Please help me , thank you
natka813 [3]

Answer:

80 degrees

Step-by-step explanation:

one half of the circle makes a straight line and that will equal 180 degrees so 60+45=105

180-105=80

so the missing angle is x=80

4 0
3 years ago
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Solve : 4(4p+6)=16 find the value of p
inna [77]

Answer:

p=-1/2

Step-by-step explanation:

4(4p+6)=16

4p+6=4

4p=4-6

4p=-2

P=-2/4

p=-1/2

7 0
3 years ago
At Max party,3/12 of the guests are 10 years old and 7/12 of the guests are 11 years old. What fraction of the guests are 10 or
Pavlova-9 [17]

Answer:

10/12

Step-by-step explanation:

3/12 + 7/12 = 10/12

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Find the inverse function for
kifflom [539]
\bf \stackrel{f(x)}{y}=\sqrt{2x-6}\qquad \qquad \stackrel{f^{-1}(x)}{y}=\cfrac{x^2+6}{2}

that is correct hmmmm, yes, I think the restriction is also correct, it has to be x > 0, because, the domain on the original, has a restriction of x⩾3, otherwise the radicand turns negative.

now, the graph of that original function is a parabola sideways opening to the right, if you include both sides of the vertex of the parabola, it will not pass the vertical-line-test and not be a function, but if you restrict it to only positive roots, so it'll only be on the 1st quadrant, then it functions ok.

that means, the range of the original function, has to stick to only 0 or positive root values, now, recall that the range of the original is the domain of the inverse.  Therefore, the domain of the inverse, will have to stick to only 0 or positive values, since it's bound to the same restriction as the original's range.

notice the picture below of both, the dashed section is the positive range for each, if you include it, the original will fail the vertical-line-test, and the inverse will fail the horizontal-line-test.

recall that for a function to have an inverse, they both must pass the vertical and horizontal line test, or be a one-to-one functions.

6 0
4 years ago
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