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tatiyna
3 years ago
15

Hey I’m bored 1 plus 1 is?

Mathematics
2 answers:
Natali5045456 [20]3 years ago
7 0
Not 2 I think it’s a carrot
Zinaida [17]3 years ago
5 0

Answer:

I thinks uhh- I thinks a carrot

Step-by-step explanation:

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Select the number that would make this statement true: 628 divided by 0.628
Amiraneli [1.4K]
The answer would be 10 to the third because if you divide that it would equal 1,000
8 0
3 years ago
PLEASE HELP WITH THIS QUESTION
Burka [1]
One nice thing about this situation is that you’ve been given everything in the same base. To review a little on the laws of exponents, when you have two exponents with the same base being:

– Multiplied: Add their exponents
– Divided: Subtract their exponents

We can see that in both the numerator and denominator we have exponents *multiplied* together, and the product in the numerator is being *divided* by the product in the detonator, so that translates to *summing the exponents on the top and bottom and then finding their difference*. Let’s throw away the twos for a moment and just focus on the exponents. We have

[11/2 + (-7) + (-5)] - [3 + 1/2 + (-10)]

For convenience’s sake, I’m going to turn 11/2 into the mixed number 5 1/2. Summing the terms in the first brackets gives us

5 1/2 + (-7) + (-5) = - 1 1/2 + (-5) = -6 1/2

And summing the terms in the second:

3 + 1/2 + (-10) = 3 1/2 + (-10) = -6 1/2

Putting those both into our first question gives us -6 1/2 - (-6 1/2), which is 0, since any number minus itself gives us 0.

Now we can bring the 2 back into the mix. The 0 we found is the exponent the 2 is being raised to, so our answer is

2^0, which is just 1.
5 0
3 years ago
How to get the equation
Olenka [21]
ITS EASY AND IF YOU TRY YOU CAN FIND THE ANSWER JUST WORK HARD AND TRY
6 0
3 years ago
Helppppppppppppppppp lol
asambeis [7]

Answer:

There are no solutions.

Step-by-step explanation:

If there is 74 and 54 but with the same 15x: there is no solution. Even with negative.

3 0
2 years ago
Read 2 more answers
226Ra has a half-life of 1599 years. How much is left after 1000 years if the initial amount was 10 g?
Ray Of Light [21]
\bf \textit{Amount for Exponential Decay using Half-Life}\\\\
A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &10\\
t=\textit{elapsed time}\to &1000\\
h=\textit{half-life}\to &1599
\end{cases}
\\\\\\
A=10\left( \frac{1}{2} \right)^{\frac{1000}{1599}}
8 0
3 years ago
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