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Kazeer [188]
2 years ago
15

You're playing the ring toss at a carnival. In one round of the game, you either hit your target and win, or you miss the target

and lose. What is the probability you will win one round of the game?
Mathematics
2 answers:
Marrrta [24]2 years ago
4 0
If you’re only playing one round, it’ll be 1/2 change you will win. So it is likely
Alina [70]2 years ago
3 0
Answer:1/2

Total probability in round 1 is 1
And there are two likely outcomes which are win and lose
And as such there is an equal probability for both to happen
Also , the sum of the two outcomes should be 1
(Win + Lose ) = 1
(1/2) + (1/2) =1
Hence the probability that round 1 is won is 1/2
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The absolute value makes it 9

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Write an inequality for the following graph
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Answer:

I am pretty sure it would be B.

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If(x) = x + 2 and h(x) = x-1, what is f • h](-3)?
deff fn [24]

Answer/Step-by-step explanation:

Composition functions are functions that combine to make a new function. We use the notation ◦ to denote a composition.

f ◦ g is the composition function that has f composed with g. Be aware though, f ◦ g is not

the same as g ◦ f. (This means that composition is not commutative).

f ◦ g ◦ h is the composition that composes f with g with h.

Since when we combine functions in composition to make a new function, sometimes we

define a function to be the composition of two smaller function. For instance,

h = f ◦ g (1)

h is the function that is made from f composed with g.

For regular functions such as, say:

f(x) = 3x

2 + 2x + 1 (2)

What do we end up doing with this function? All we do is plug in various values of x into

the function because that’s what the function accepts as inputs. So we would have different

outputs for each input:

f(−2) = 3(−2)2 + 2(−2) + 1 = 12 − 4 + 1 = 9 (3)

f(0) = 3(0)2 + 2(0) + 1 = 1 (4)

f(2) = 3(2)2 + 2(2) + 1 = 12 + 4 + 1 = 17 (5)

When composing functions we do the same thing but instead of plugging in numbers we are

plugging in whole functions. For example let’s look at the following problems below:

Examples

• Find (f ◦ g)(x) for f and g below.

f(x) = 3x + 4 (6)

g(x) = x

2 +

1

x

(7)

When composing functions we always read from right to left. So, first, we will plug x

into g (which is already done) and then g into f. What this means, is that wherever we

see an x in f we will plug in g. That is, g acts as our new variable and we have f(g(x)).

g(x) = x

2 +

1

x

(8)

f(x) = 3x + 4 (9)

f( ) = 3( ) + 4 (10)

f(g(x)) = 3(g(x)) + 4 (11)

f(x

2 +

1

x

) = 3(x

2 +

1

x

) + 4 (12)

f(x

2 +

1

x

) = 3x

2 +

3

x

+ 4 (13)

Thus, (f ◦ g)(x) = f(g(x)) = 3x

2 +

3

x + 4.

Let’s try one more composition but this time with 3 functions. It’ll be exactly the same but

with one extra step.

• Find (f ◦ g ◦ h)(x) given f, g, and h below.

f(x) = 2x (14)

g(x) = x

2 + 2x (15)

h(x) = 2x (16)

(17)

We wish to find f(g(h(x))). We will first find g(h(x)).

h(x) = 2x (18)

g( ) = ( )2 + 2( ) (19)

g(h(x)) = (h(x))2 + 2(h(x)) (20)

g(2x) = (2x)

2 + 2(2x) (21)

g(2x) = 4x

2 + 4x (22)

Thus g(h(x)) = 4x

2 + 4x. We now wish to find f(g(h(x))).

g(h(x)) = 4x

2 + 4x (23)

f( ) = 2( ) (24)

f(g(h(x))) = 2(g(h(x))) (25)

f(4x

2 + 4x) = 2(4x

2 + 4x) (26)

f(4x

2 + 4x) = 8x

2 + 8x (27)

(28)

Thus (f ◦ g ◦ h)(x) = f(g(h(x))) = 8x

2 + 8x.

4 0
3 years ago
Simplify completely quantity x squared plus 4 x minus 45 all over x squared plus 10 x plus 9 and find the restrictions on the va
dem82 [27]
(x² + 4x - 45)/(x² + 10x + 9) 
<span>
Numerator = N = x² + 4x - 45 </span>
= x² + 9x - 5x - 45 
= (x² + 9x) - (5x + 45) 
= x(x + 9) - 5(x + 9) 
= (x + 9)(x - 5) 
<span>
Denominator = D = x² + 10x + 9 </span>
= x² + x + 9x + 9 
= (x² + x) + (9x + 9) 
= x(x + 1) + 9(x + 1) 
= (x + 1)(x + 9) 
<span>
Hence, the given expr. = N/D </span>
= {(x + 9)(x - 5)}/{(x + 1)(x + 9) 
= (x - 5)/(x + 1) 
<span>
Restrictions : x ≠ - 1, x = 5 </span>


I hope my answer has come to your help. Thank you for posting your question here in Brainly.
7 0
4 years ago
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Willie had 55 baseball cards after trading with his friends. He traded 5 cards for one special card. Lee gave him 11 cards for a
Nikolay [14]

Answer:

49 baseball cards.

Step-by-step explanation:

First you want to add 5 cards to the 55 for the 5 he traded for the one. You get 60. Then subtract the 11 cards that he was given for the 1. You end up with 49 baseball cards.

8 0
3 years ago
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