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fomenos
3 years ago
15

What is the trigonometric ratio for cosC ?

Mathematics
2 answers:
erik [133]3 years ago
7 0

Answer:

CosC=0.882

Step-by-step explanation:

From the figure, it is given that ABC is a right angled triangle such that AB=24, BC=45 and AC=51.

Now, as we know that the value of CosC is given as:

CosC=\frac{Base}{Hypotenuse}

From the figure, the value of Base is =BC=45 and hypotenuse is=AC=51, therefore:

CosC=\frac{BC}{AC}

CosC=\frac{45}{51}

CosC=0.882

Thus, the value of CosC is 0.882.

Usimov [2.4K]3 years ago
5 0
Sin C = 24/ 51
hope this helps
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Scores on a final exam taken by 1200 students have a bell shaped distribution with mean=72 and standard deviation=9
SVETLANKA909090 [29]

Answer:

a. 72

b. 816

c. 570

d. 30

Step-by-step explanation:

Given the graph is a bell - shaped curve. So, we understand that this is a normal distribution and that the bell - shaped curve is a symmetric curve.

Please refer the figure for a better understanding.

a. In a normal distribution, Mean = Median = Mode

Therefore, Median = Mean = 72

b. We have to know that 68% of the values are within the first standard deviation of the mean.

i.e., 68% values are between Mean $ \pm $ Standard Deviation (SD).

Scores between 63 and 81 :

Note that 72 - 9 = 63 and

72 + 9 = 81

This implies scores between 63 and 81 constitute 68% of the values, 34% each, since the curve is symmetric.

Now, Scores between 63 and 81 = $ \frac{68}{100} \times 1200 $

= 68 X 12 = 816.

That means 816 students have scored between 63 and 81.

c. We have to know that 95% of the values lie between second Standard Deviation of the mean.

i.e., 95% values are between Mean $ \pm $ 2(SD).

Note that 90 = 72 + 2(9) = 72 + 18

Also, 54 = 63 - 18.

Scores between 54 and 90 totally constitute 95% of the values. So, Scores between 72 and 90 should amount to $ \frac{95}{2} \% $ of the values.

Therefore, Scores between 72 and 90 = $ \frac{95}{2(100)} \times 1200 = \frac{95}{200} \times 1200  $

$ \implies 95 \times 12 $ = 570.

That is a total of 570 students scored between 72 and 90.

d. We have to know that 5 % of the values lie on the thirst standard Deviation of the mean.

In this case, 5 % of the values lie between below 54 and above 90.

Since, we are asked to find scores below 54. It should be 2.5% of the values.

So, Scores below 54 = $ \frac{2.5}{100} \times 1200 $

= 2.5 X 12 = 30.

That is, 30 students have scored below 54.

8 0
2 years ago
The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
3.30, -√10, 17/5, √11 least to greatest
Vilka [71]

Answer:

-√10,√11 , 3.30, 17/5

Step-by-step explanation:

-√10,√11 , 3.30, 17/5

17/5 is 3.4

the 10 is a negative so its the smallest

11 square root is a imiganery

7 0
3 years ago
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A spinner has 6 equally divided sections labeled A, B, C, D, E and F. After spinning the spinner, a number cube is rolled. What
bagirrra123 [75]

Answer: \dfrac{2}{9}

Step-by-step explanation:

Given

The spinner has 6 equal sections A, B, C, D, E, and F

The two events occurred one after the other. So, the probability is the product of the probabilities of each event.

There are two consonants in the given 6 letter

The probability of landing over a consonant  is

P_1=\dfrac{2}{6}

The number greater than 2 in a cube are 3,4,5,6

So, probability corresponding to it

P_2=\dfrac{4}{6}

So, the required probability is

\Rightarrow P=P_1\times P_2\\\Rightarrow P=\dfrac{2}{6}\times \dfrac{4}{6}\\\\\Rightarrow P=\dfrac{8}{36}\\\\\Rightarrow P=\dfrac{2}{9}

8 0
3 years ago
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Anestetic [448]

Answer:

98

Step-by-step explanation:

by looking at the bottom the answer is 98

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