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3 years ago

Please explain me and tell me the right answer.

Mathematics

1 answer:

Shkiper50 [21]3 years ago

4 0

Basically, it asks you to find the piece of data that is 1/10th of the overall shoe sales on a given day. As the number of shoes sold per day is 400, the piece of data you are looking for is 40. Meaning the answer is 'High heels sold on Friday'

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Solve for x: 2 - 6 = 0 X = Help plz

antiseptic1488 [7]

Answer:

because when you subtract 6 from 6 you get 0

6 - 6 = 0

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3 years ago

5 inches is what fraction of a foot

ipn [44]

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5/12

Step-by-step explanation:

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3 years ago

Match the vocab terms with the correct definition.

Anna007 [38]

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3 years ago

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Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

3 years ago

The first term in a sequence is 3 The term-to-term rule is + 8 What is the 5th term?

galben [10]

2nd term: 3+8
= 11
3rd term: 11+8
= 19
4th term: 19+8
= 27
5th term: 27+8
= 35

OR
((n-1)x8)+3

7 0

3 years ago