9514 1404 393
Answer:
- maximum: 15∛5 ≈ 25.6496392002
- minimum: 0
Step-by-step explanation:
The minimum will be found at the ends of the interval, where f(t) = 0.
The maximum is found in the middle of the interval, where f'(t) = 0.
![f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)](https://tex.z-dn.net/?f=f%28t%29%3D%5Csqrt%5B3%5D%7Bt%7D%2820-t%29%5C%5C%5C%5Cf%27%28t%29%3D%5Cdfrac%7B20-t%7D%7B3%5Csqrt%5B3%5D%7Bt%5E2%7D%7D-%5Csqrt%5B3%5D%7Bt%7D%3D%5Csqrt%5B3%5D%7Bt%7D%5Cleft%28%5Cdfrac%7B4%285-t%29%7D%7B3t%7D%5Cright%29)
This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...
f(5) = (∛5)(20-5) = 15∛5
The absolute maximum on the interval is 15∛5 at t=5.
Answer:
2PA
Step-by-step explanation:
Answer:
90.393
Step-by-step explanation:
Answer: 2 inches, 3 inches, or 3.125 and 2.083
Explanations:
The simplest way is to take 20% of the 2.5 inches and go that much above & below 2.5 inches.
2.5 x 20% = 2.5 x 0.20 = 0.5
So 2.5 - 0.5 = 2 inches was predicted
And 2.5 + 0.5 = 3 inches was predicted.
The more complicated way is to see number + 20% of that number = 2.5, and what number - 20% = 2.5.
Which solution sounds more like what you’re doing in class right now?
If it’s the more complicated way:
0.8x = 2.5 (80% of the predicted rain value equals 2.5)
x = 3.125 inches was predicted
1.2x = 2.5 (120% of the predicted rain value equals 2.5)
x = 2.083 inches was predicted
Sorry, this is probably confusing. Let me know what questions you have.
Answer:
1:3.7
Step-by-step explanation:
1331/27
Then cube root
3.66666666667
Round
3.7
(i believe)
