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3 years ago

15x110=(15x100)+(15xn)

2 answers:

8 0

The answer is n=10 because 15x110=1650 so (15x100)+(15xn) has to equal 1650. 15x100=1500
So you subtract 1650-1500 and it gives you 150, so you divide 150 divided by 15 and it equals 10,so the answer is 10

Sonbull [250]3 years ago

5 0

Your answer is n=10. I hope it helped

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Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

2 years ago

There are 16 students playing kickball. Two students leave to go play hopscotch. How do you write the fraction of children left

olga55 [171]

Answer:

7/8

Step-by-step explanation:

When 16 students are playing kickball, there are 16/16 students on the field. After 2 leave, this becomes 16-2/16, therefore 14/16 which is divisible by 2. and therefore 7/8, which the numerator and denominator have no common divisors.

6 0

3 years ago

Colton left his house for work and was gone 5 hours. He spent a total of } hour driving to and from work and didn't go anywhere

Solnce55 [7]

Answer:

4 $\frac{3}{4}$ hours

Step-by-step explanation:

he was gone for 5 $\frac{1}{4}$ hours, he spent $\frac{1}{2}$ an hour driving.

5 $\frac{1}{4}$ - $\frac{1}{2}$ = 4 $\frac{3}{4}$ hours at work.

6 0

2 years ago

Help with inequality

Alona [7]

Answer:

1. x>20 2. x≤1 3.x<4 4.x>9 5.x≥-13

6 0

2 years ago

Lily weighs 57.7 kg while her sister weighs 59.02 kg, how much more does Lily's sister weigh then her? Please provide the calcul

PilotLPTM [1.2K]

The answer is 1.32

For this calculation, assuming that no conversions are required, the calcitonin goes as follows:

All that is needed is to subtract 57.7 from 59.02.

59.02 - 57.7 = ?

59.02 - 57.7 = 1.32

Hope this helps! Have a great day.

5 0

2 years ago