Let h = height of the box,
x = side length of the base.
Volume of the box is

.
So

Surface area of a box is S = 2(Width • Length + Length • Height + Height • Width).
So surface area of the box is


The surface are is supposed to be the minimum. So we'll need to find the first derivative of the surface area function and set it to zero.

![4x = \frac{460}{ x^{2} } \\ 4x^{3} = 460 \\ x^{3} = 115 \\ x = \sqrt[3]{115} = 4.86](https://tex.z-dn.net/?f=%204x%20%3D%20%5Cfrac%7B460%7D%7B%20x%5E%7B2%7D%20%7D%20%20%5C%5C%20%204x%5E%7B3%7D%20%3D%20460%20%20%5C%5C%20x%5E%7B3%7D%20%3D%20115%20%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B115%7D%20%3D%204.86%20)
Then

So the box is 4.86 in. wide and 4.87 in. high.
The answer is D, that is negative
12.38 in expanded form is write like:-
10 + 2 + .3 + .08 = 12.38
To write a number in expanded form just means to write the number in a layout and when you add it up it will become the number you needed to write in expanded form.
So, 12.38 written in expanded form is:- 10 + 2 + .3 + 0.8
Hope i helped ya!!
Answer:
37.59 nautical miles
Explanation:
Distance = Speed x Time
The speed of the first ship = 12 knots
Thus, the distance covered after 1.5 hours

The speed of the second ship = 22 knots
Thus, the distance covered after 1.5 hours

The diagram representing the ship's path is drawn and attached below:
The angle at port = 90 degrees.
The triangle is a right triangle.
Using Pythagorean Theorem:
![\begin{gathered} c^2=a^2+b^2 \\ c^2=18^2+33^2 \\ c^2=324+1089 \\ c^2=1413 \\ c=\sqrt[]{1413} \\ c=37.59\text{ miles} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20c%5E2%3Da%5E2%2Bb%5E2%20%5C%5C%20c%5E2%3D18%5E2%2B33%5E2%20%5C%5C%20c%5E2%3D324%2B1089%20%5C%5C%20c%5E2%3D1413%20%5C%5C%20c%3D%5Csqrt%5B%5D%7B1413%7D%20%5C%5C%20c%3D37.59%5Ctext%7B%20miles%7D%20%5Cend%7Bgathered%7D)
The two ships are 37.59 nautical miles apart after 1.5 hours.
19 is the answer for this question