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Nonamiya [84]
3 years ago
8

Can someone give me the answer for this?

Mathematics
1 answer:
RoseWind [281]3 years ago
3 0
Just look up the different formulas.
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If an open box has a square base and a volume of 115 in.3 and is constructed from a tin sheet, find the dimensions of the box, a
Karolina [17]
Let h = height of the box,
x = side length of the base.

Volume of the box is  V=x^{2} h = 115. 
So h = \frac{115}{ x^{2} }

Surface area of a box is S = 2(Width • Length + Length • Height + Height • Width).
So surface area of the box is
S = 2( x^{2}  + hx + hx)  \\ = 2 x^{2}  + 4hx  \\  = 2 x^{2}  + 4( \frac{115}{ x^{2} } )x
= 2 x^{2} + \frac{460}{x}
The surface are is supposed to be the minimum. So we'll need to find the first derivative of the surface area function and set it to zero.

S' = 4x- \frac{460}{ x^{2} }  = 0
4x = \frac{460}{ x^{2} }  \\  4x^{3} = 460  \\ x^{3} = 115  \\ x =  \sqrt[3]{115} = 4.86
Then h=  \frac{115}{4.86^{2}} = 4.87
So the box is 4.86 in. wide and 4.87 in. high. 

5 0
3 years ago
Read 2 more answers
I need help fast !!!
Volgvan
The answer is D, that is negative
6 0
3 years ago
Read 2 more answers
12.38 in expanded form
vitfil [10]
12.38 in expanded form is write like:-

10 + 2 + .3 + .08 = 12.38

To write a number in expanded form just means to write the number in a layout and when you add it up it will become the number you needed to write in expanded form. 

So, 12.38 written in expanded form is:- 10 + 2 + .3 + 0.8

Hope i helped ya!! 
4 0
3 years ago
two ships leave a port at the same time. the first ship sails on a bearing of 55° at 12 knots (natural miles per hour) and the s
Korvikt [17]

Answer:

37.59 nautical miles

Explanation:

Distance = Speed x Time

The speed of the first ship = 12 knots

Thus, the distance covered after 1.5 hours

\begin{gathered} =12\times1.5 \\ =18\text{ miles} \end{gathered}

The speed of the second ship = 22 knots

Thus, the distance covered after 1.5 hours

\begin{gathered} =22\times1.5 \\ =33\text{ miles} \end{gathered}

The diagram representing the ship's path is drawn and attached below:

The angle at port = 90 degrees.

The triangle is a right triangle.

Using Pythagorean Theorem:

\begin{gathered} c^2=a^2+b^2 \\ c^2=18^2+33^2 \\ c^2=324+1089 \\ c^2=1413 \\ c=\sqrt[]{1413} \\ c=37.59\text{ miles} \end{gathered}

The two ships are 37.59 nautical miles apart after 1.5 hours.

8 0
1 year ago
Whats does 9+10 equal to?
Ymorist [56]
19 is the answer for this question
7 0
3 years ago
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