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3 years ago

9

How far would someone driving a car at 60 mph for 4.5 hours travel?

1 answer:

mel-nik [20]3 years ago

8 0

They would drive
60 + 60 + 60 + 60 + 30
which equals
270 miles for 4.5 hours

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100 POINTS 10 QUESTIONS PLEASE HELP PICTURES BELOW PLEASE SPECIFY WHICH QUESTION YOU ARE ANSWERING

Semenov [28]

Answer:

The answers are $\frac{2}{5}, \frac{1}{4}, \frac{1}{10}, \frac{5}{2}, \frac{5}{8}, \frac{4}{1}, \frac{8}{5},$ and $\frac{10}{1}$ .

Step-by-step explanation:

Proportions are fractions that can be made by using the given numbers, which in this case are 2, 5, 8, and 20. Let's pair each one with the other three and then simplify if possible.

First, let's begin with 2:

$\frac{2}{5} = \frac{2}{5}$

$\frac{2}{8} = \frac{1}{4}$

$\frac{2}{20} = \frac{1}{10}$

Then, let's do 5:

$\frac{5}{2} = \frac{5}{2}$

$\frac{5}{8} = \frac{5}{8}$

$\frac{5}{20} = \frac{1}{4}$

Note that we already have $\frac{1}{4}$ , so we do not need to include an additional one.

Now, let us do 8:

$\frac{8}{2} = \frac{4}{1}$

$\frac{8}{5} = \frac{8}{5}$

$\frac{8}{20} = \frac{2}{5}$

See how we already have $\frac{2}{5}$ , so we won't have to include that as well.

Finally, let's do 20:

$\frac{20}{2} = \frac{10}{1}$

$\frac{20}{5} = \frac{4}{1}$

$\frac{20}{8} = \frac{5}{2}$

Now see that we already have both $\frac{4}{1}$ and $\frac{5}{2}$ , so we won't have to include both of them, as they are both extras.

Hence, the answers are $\frac{2}{5}, \frac{1}{4}, \frac{1}{10}, \frac{5}{2}, \frac{5}{8}, \frac{4}{1}, \frac{8}{5},$ and $\frac{10}{1}$ .

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>

8 0

2 years ago

Read 2 more answers

11. Find the missing number 1:2 = 3:<br> O A. 2<br> OB. 1<br> OC.3<br> OD. 6

Ilia_Sergeevich [38]

Yh I think the missing number will be 6 because they are equivalent to 1:2

3 0

2 years ago

Read 2 more answers

The height in feet is modelled by the function below, where the t is in

Sedaia [141]

The object reaches the lowest height at 5 seconds

<h3>How to determine the time?</h3>

The function is given as:

f(t) = -2t² +22t + 6

Differentiate the function

f'(t) = -4t +22

Set to 0

-4t +22 = 0

Subtract 22 from both sides

-4t = -22

Divide both sides by -4

t = 5.5

Remove decimal points

t = 5

Hence, the object reaches the lowest height at 5 seconds

Read more about quadratic functions at:

brainly.com/question/1214333

#SPJ1

6 0

1 year ago

Please help, math work

NikAS [45]

Y = 3x + 5 because the slope is 3/1 and 0 = 5

6 0

2 years ago

Someone just answer this math question thingie lol. you’ll get 33 points G

Stels [109]

1) $(-2x+4)+(x-6)$ is simplified into $=-x-2$

2) $(uv-3)+(4uv+1)$ is simplified into $5uv-2\\$

3) $(11x-8)-(2x+3)$ is simplified into $-9x-11$

4) $(x^2-4)-(x-2)$ is simplified into $x^2-x-2$

5) $(12-3t-7t^2)+(1+3t-t^2)$ is simplified into $-8t^2+13$

Step-by-step explanation:

We need to solve the polynomials.

1) $(-2x+4)+(x-6)$

Solving:

$(-2x+4)+(x-6)\\=-2x+4+x-6\\Combining\,\,like\,\,terms:\\=-2x+x+4-6\\=-x-2$

So, $(-2x+4)+(x-6)$ is simplified into $=-x-2$

2) $(uv-3)+(4uv+1)$

Solving:

$(uv-3)+(4uv+1)$

Expanding:

$=uv-3+4uv+1\\Combining\,\,like\,\,terms:\\=uv+4uv-3+1\\=5uv-2\\$

So, $(uv-3)+(4uv+1)$ is simplified into $5uv-2\\$

3) $(11x-8)-(2x+3)$

Solving:

$(11x-8)-(2x+3)$

Expanding:

$=11x-8-2x-3\\Combining\,\,like\,\,terms:\,\,\\=11x-2x-8-3\\=-9x-11$

So, $(11x-8)-(2x+3)$ is simplified into $-9x-11$

4) $(x^2-4)-(x-2)$

Solving:

$(x^2-4)-(x-2)$

Expanding:

$=x^2-4-x+2\\Combining\,\,like\,\,terms:\\=x^2-x-4+2\\=x^2-x-2$

SO, $(x^2-4)-(x-2)$ is simplified into $x^2-x-2$

5) $(12-3t-7t^2)+(1+3t-t^2)$

Solving:

$(12-3t-7t^2)+(1+3t-t^2)$

Expanding:

$=12-3t-7t^2+1+3t-t^2\\Combining\,\,like\,\,terms:\\=12+1-3t+3t-7t^2-t^2\\=13+0t-8t^2\\=-8t^2+13$

So, $(12-3t-7t^2)+(1+3t-t^2)$ is simplified into $-8t^2+13$

Keywords: Solving Polynomials

Learn more about solving Polynomials at:

#learnwithBrainly

5 0

2 years ago

Read 2 more answers