Answer:
(-5.77, 6.46)
Step-by-step explanation:
15x + 9y = 45 ----------- i
9x + 8y = 12----------------ii
Multiply equation i by 9 the coefficient of x in equ ii
And equation ii by 15 the coefficient of x in equ I
9 x 15x + 9y = 45 ----------- i
15 x 9x + 8y = 12----------------ii
135x+81y = 405
135x+120y= 180
Subtract equation ii from I
135x-135x+81y-(+120y)= 405-180
-39y=225
y = 225/-39 = -5.77
Insert the value of y in equ i
15x + 9y = 45
15x+9(-5.77) = 45
15x-51.92=45
15x = 45+51.92
15x= 96.92
x = 96.92/15= 6.46
(x,y) = (-5.77, 6.46)
x = 6.92/15
we have
we know that
The absolute value has two solutions
Subtract
both sides
Step 1
Find the first solution (Case positive)
![-[+(x-12)]=-0.75](https://tex.z-dn.net/?f=-%5B%2B%28x-12%29%5D%3D-0.75)

Subtract
both sides


Multiply by
both sides

Step 2
Find the second solution (Case negative)
![-[-(x-12)]=-0.75](https://tex.z-dn.net/?f=-%5B-%28x-12%29%5D%3D-0.75)

Adds
both sides


<u>Statements</u>
<u>case A)</u> The equation will have no solutions
The statement is False
Because the equation has two solutions------> See the procedure
<u>case B)</u> A good first step for solving the equation is to subtract 0.5 from both sides of the equation
The statement is True -----> See the procedure
<u>case C)</u> A good first step for solving the equation is to split it into a positive case and a negative case
The statement is False -----> See the procedure
case D) The positive case of this equation is 0.5 – |x – 12| = 0.25
The statement is False
Because the positive case is
-----> see the procedure
case E) The negative case of this equation is x – 12 = –0.75
The statement is True -----> see the procedure
<u>case F)</u> The equation will have only 1 solution
The statement is False
Because The equation has two solutions------> See the procedure
Answer: L= 90-3 i hope this helps u :)
Answer:
-2
Step-by-step explanation:
We can set it equal to zero
2x+4 = 0
2x =-4
x = -2
<h2>
Answer:</h2><h2>
2(x+17)</h2><h2>
Step-by-step explanation:</h2>
To be honest I am not sure
Good Luck Sorry if it is wrong.