So 1 head per squirel and 1 head per bird
4 legs per squirel and 2 legs per bird
s=number of squirels
b=birds
the equatinos should be
1b+1s=number of heads=16
and
2b+4s=number of legs=44
(note 2b=2 times b)
so we aolve

b+s=16 and 2b+4s=44
simplify the second equaiton by divideinb by 2
2b+4s=44
divide 2
b+2s=22

b+s=16
and
b+2s=22
we can actually add the two equations together with the first one made negative
-b-s=-16
<u>b+2s=22+</u>
0b+1s=6
s=6
subsitute
b+s=16
b+6=16
subtract 6 from both sides
b=10

10 birds
answer is c

4 0

2 years ago

Which is larger 80% or 1/8

d1i1m1o1n [39]

So 1/8 as a percentage is 12.5%.

80% is greater than 12/5%.

So your answer would be 80%.

4 0

2 years ago

Read 2 more answers

Find the values of s_1 and r for a geometric sequence with s_4= 18 and s_6= 72<br>

dmitriy555 [2]

<h3>Answer: Choice A</h3>

$s_1 = 2.25, \ r = 2$

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Work Shown:

$s_4 = 18\text{ is the fourth term}\\\\s_5 = r*s_4 = 18r\\\\s_6 = r*s_5 = r*(18r) = 18r^2 = 72\\\\\text{So,}\\\\18r^2 = 72\\\\r^2 = \frac{72}{18}\\\\r^2 = 4\\\\r = \sqrt{4}\\\\r = 2$

Use that r value and $s_4 = 18$ to find the first term

$s_n = s_1*(r)^{n-1}\\\\s_4 = s_1*(2)^{4-1}\\\\18 = s_1*8\\\\s_1 = \frac{18}{8}\\\\s_1 = 2.25$

You could use $s_6 = 72$ in place of $s_4 = 18$ (just make sure to use n = 6 instead of n = 4).

4 0

3 years ago