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3 years ago

What is the equation for the vertical asymptote of the function shown below?

Mathematics

2 answers:

Nikitich [7]3 years ago

8 0

Answer:

-3

Step-by-step explanation:

apex :) just did it

Katarina [22]3 years ago

6 0

Answer:

APEX x=-3

Step-by-step explanation:

x+3=0->x=-3

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Faye is 5 ft 5 in. Faye is 10 in. Shorter than her older brother. How tall is Faye’s older brother?

victus00 [196]

Answer:

He's 6 ft "5"

Step-by-step explanation:

Added 10

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3 years ago

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11 The net force on a vehicle that is accelerating at a rate of 1.5 m/s² is 2,800 newtons. What is

ololo11 [35]

Answer:

$Mass = 1867kg$

Step-by-step explanation:

Given

$Force = 2800N$

$Acceleration = 1.5m/s^2$

Required

Determine the mass of the vehicle

This question will be answered using Newton's second law

$Force = Mass * Acceleration$

Substitute values for Force and Acceleration

$2800 = Mass * 1.5m/s^2$

Make Mass the subject

$Mass = \frac{2800N}{1.5m/s^2}$

$Mass = 1866.6667kg$

$Mass = 1867kg$ ---- approximated

<em>Hence, the mass of the vehicle is 1867kg</em>

4 0

3 years ago

Is 2.6 bigger than 2.661

Sauron [17]

2.6 = 2.600
So, 2.6 is not bigger than 2.661

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3 years ago

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A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte

AleksandrR [38]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

SR= h=height of the statue

$\angle SPR$ =Angle subtended by the statue to where you are standing.

$\angle x=\angle RPQ$ = which is unknown.

Let us begin solving now. The first step is to find the angle $\angle x$ which can be found by using the following trigonometric ratio in $\Delta PQR$ :

$tan(x)=\frac{RQ}{PQ} =\frac{21}{57}$

Which gives $\angle x$ to be:

$\angle x=tan^{-1}(\frac{21}{57})\approx20.22^{0}$

Now, we know that $\angle x$ and $\angle SPR$ can be added to give us the complete angle $\angle SPQ$ in the right triangle $\Delta SPQ$ .

We can again use the tan trigonometric ratio in $\Delta SPQ$ to solve for the height of the statue, h.

This can be done as:

$tan(\angle SPQ)=\frac{SQ}{PQ}$

$tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}$

$tan(27.32^0)=\frac{h+21}{57}$

$\therefore h+21=57tan(27.32^0)$

$h\approx8.45 ft$

Thus, the height of the statue is approximately, 8.45 feet.

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3 years ago

Pls help due in 40 minutes Pls I will give brainliest But pls only right answers

defon

Answer:

6. 15.2

Step-by-step explanation:

60.8 divided by 4 so the constant is 15.2 because 15.2 x 4 is 60.80

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2 years ago

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