Answer:
11x+2
Step-by-step explanation:
Answer:
Section A = 25,000 seats
Section B = 14,600 seats
Section C = 10,400 seats
Step-by-step explanation:
Total Seats = 50,000
Seats in Section A cost = $30
Seats in Section B cost = $24
Seats in Section C cost = $18
Total sales from the event = $1,287,600
No. of Seats in section A = No. seats in Section B + No. seats in Section C
A = B + C
or, 2A = 50,000
A = 25,000 seats @ $30/seat = $750,000
B + C = 25,000
24B + 18C = 537,600
24B + 18(25,000 - B) = 537,600
24B + 450,000 - 18B = 537,600
6B = 87600
B = 14,600
C = 10,400
Hence;
A = 25,000 seats
B = 14,600 seats
C = 10,400 seats
Answer:

Step-by-step explanation:
⇒ 
⇒ 
⇒ 
⇒ 
Answer:
1481
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given:
A car starts with a dull tank of gas
1/7 of the gas has been used around the city.
With the rest of the gas in the car, the car can travel to and from Ottawa three times.
Question asked:
What fractions of a tank of gas does each complete trip to Ottawa use?
Solution:
Fuel used around the city = 
Remaining fuel after driving around the city = 1 -
= 
According to question:
As from the rest of the gas in the car that is
, the car can complete 3 trip to Ottawa which means,
By unitary method:
The car can complete 3 trip by using =
tank of gas.
The car can complete 1 trip by using = 
=
= 
=
tank of gas
Thus,
tank of gas used for each complete trip to Ottawa.