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Sholpan [36]
3 years ago
13

Consider the system of equations. y = 3x + 2       y = − 2 3 x − 4 Explain why these particular equations can be graphed immedia

tely.
Mathematics
1 answer:
inessss [21]3 years ago
3 0

Answer:

These equations are in slope-intercept form. I can use the y-intercept and slope to graph both lines. I plot the y-intercept and use rise over run to locate another point on the line. Then, I can draw a line through the two points.

Step-by-step explanation:

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A stack of one hundred fifty cards is placed next to a ruler, and the height of the stack is measured to be 5/8 inches.
DaniilM [7]
Divide 5/8 by 150, to see how thick each is, that'll give you 150 even pieces that add up to 5/8

\bf \cfrac{\frac{5}{8}}{150}\implies \cfrac{\frac{5}{8}}{\frac{150}{1}}\implies \cfrac{5}{8}\cdot \cfrac{1}{150}\implies \cfrac{1}{8\cdot 30}\implies \cfrac{1}{240}
5 0
3 years ago
Answer this question, and dnt answer it if u dnt know the answer :|
Alina [70]

Answer: 45

Step-by-step explanation:

The sides are 2x,3x,4x

Add them up and you have 9x=45

8 0
2 years ago
To rent a bounce house: At Mike's Bounce Shop costs $30 plus $2 per hour. At Jose's Bounce Rentals, it costs $12 plus $8 per hou
ANEK [815]

Answer: After 3 hours both will have the same cost.

Step-by-step explanation:

Let x = Number of hours and y be the total cost.

Total cost = Initial cost + (cost per hour)(Number of hours)

At Mike's Bounce Shop,

Total cost (y)= 30+2x

At Jose's Bounce Rentals,

Total cost(y) =  12+8x

When both shops have the same cost, then

12+8x=30+2x\\\\\Rightarrow\ 8x-2x=30-12\\\\\Rightarrow\ 6x=18\\\\\Rightarrow\ x=3

Total cost = 12+8(3)=12+24=$36

Hence, After 3 hours both will have the same cost.

3 0
2 years ago
The present age of father is thrice as old as the age of daughter 5 years ago. If 5 years hence ,the age of father will be twice
pav-90 [236]

Answer:

<em>Hence the daughter's present age is 15 years</em>

<em>The fathers present age is 35 years</em>

<em></em>

Step-by-step explanation:

Let the present age of daughter be x

Let the present age of father be y

5 years ago;

Daughter's age = x - 5

Fathers age = y - 5

If the present age of father is thrice as old as the age of daughter 5 years ago, then;

y - 5 = 3(x-5)

y - 5 = 3x-15

y = 3x - 10 .... 1

In 5 years time;

Daughters age = x + 5

Fathers age = y + 5

If the age of father will be twice the age of his daughter in 5 years time then;

y+5 = 2(x+5)

y+5 = 2x + 10

y = 2x + 5 .....2

Equate 1 and 2;

3x - 10 = 2x + 5

3x - 2x = 5 + 10

x = 15

Since y = 2x + 5

y = 2(15) + 5

y = 35

<em>Hence the daughter's present age is 15 years</em>

<em>The fathers present age is 35 years</em>

<em></em>

3 0
3 years ago
Help as soon as possible<br> The greatest common factor of y^4. y^6 and y^5 is
olchik [2.2K]

Answer:

Answer:GCF: y^4

Step-by-step explanation:

Factors of:

y^4= (y) (y) (y) (y) = y^4 (1)

y^5 = (y) (y) (y) (y) (y) = y^4 (y)

y^6 = (y) (y) (y) (y) (y) (y) = y^4(y^2)

6 0
2 years ago
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