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lutik1710 [3]
4 years ago
5

The expression 3(x-9) is equivalent to

Mathematics
1 answer:
Inessa05 [86]4 years ago
8 0
The answer to this question would be D. 3(x)-3(9)
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3 years ago
Which function should be used to when evaluating the function at x = −5? HELP ASAP!!
Furkat [3]

<u>Given</u>:

Given that the function p(x)=\left\{\begin{array}{ll}\frac{1}{4} x^{2}+1 & \text { if } x \leq 3 \\\frac{1}{4} x+2.5 & \text { if } x>3\end{array}\right.

We need to determine the function to evaluate when x = -5.

<u>Function</u>:

The function is given two interval. The interval x\leq 3 means that x takes all values less than or equal to 3.

And the interval x>3 means that x takes all values greater than 3.

We need to determine the function that takes the limit when x = -5.

From the two limits, the limit x = -5 lie in the interval x\leq 3 because the interval takes all x values less than or equal to 3.

Hence, the function is p(x)=\frac{1}{4} x^{2}+1

Thus, Option A is the correct answer.

4 0
4 years ago
Which solution to the equation 3/2g+8 g+2/g^2-16 is extraneous? A. g = –4 B. g = –4 and g = 16
ollegr [7]

im assuming the equation is:-

3 / (2g + 8) = (g + 2) / (g^2 - 16)

3(g^2 - 16) = (2g + 8)(g + 2)

3g^2 - 48 = 2g^2 + 4g + 8g + 16

Answer is A  x = -4

3g^2 - 2g^2 - 12g - 64 = 0

g^2 - 12g - 64 = 0

( g + 4)(g - 16) = 0

g = - 4, 16.

Test these solutions:-

g = -4  

left side = 3/0    which is indeterminate

right side = -2/0  indeterminate

So x = -4 is extraneous.

x = 16:- LHS = 0.075  RHS =  0.075  so x = 16 is a root.  


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