Answer:THE CORRECT ANSWER IS (A. -42)
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<span>The quadrilateral ABCD have vertices at points A(-6,4), B(-6,6), C(-2,6) and D(-4,4).
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<span>Translating 10 units down you get points A''(-6,-6), B''(-6,-4), C''(-2,-4) and D''(-4,-6).
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Translaitng <span>8 units to the right you get points A'(2,-6), B'(2,-4), C'(6,-4) and D'(4,-6) that are exactly vertices of quadrilateral A'B'C'D'.
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</span><span>Answer: correct choice is B.
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Answer:
Wouldn't it be 1/3 ??
because there is one column filled and there are three columns so that would make it 1/3 out of 3
Hey <span>kirinaallison, thanks for submitting your question to Brainly!
The answer is </span>


+5x - 2x - 10
x(x+5) - 2 (x+5) - 2(x+5)
(x + 5) (x-2)
Hope my answer was well explained if you have any more questions reply to my answer. :)
Let's first get the coefficients of the numerator: x^4 - 2x^3 + x + 3 = 1, -2, 0, 1, 3
<em>There is no x^2 in the expression, thus, the coefficient for x^2 = 0</em>
Zero of the denominator: x + 3; x = -3
Using synthetic division,
-3 I 1 -2 0 1 3
I_________________
-3 I 1 -2 0 1 3
I_________________
1
-3 I 1 -2 0 1 3
I_____-3___________
1 -5
-3 I 1 -2 0 1 3
I_____-3__15_______
1 -5 15
-3 I 1 -2 0 1 3
I_____-3__15_-45____
1 -5 15 -44
-3 I 1 -2 0 1 3
I_____-3__15_-45____
1 -5 15 -44
-3 I 1 -2 0 1 3
I_____-3__15_-45_132__
1 -5 15 -44 135
The remainder is 135. Which transforms it into 135/x+3.
Thus, the quotient of x^4 - 2x^3 + x + 3 divided by x + 3 is: