1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zhuklara [117]
3 years ago
12

Please help due soon

Mathematics
2 answers:
Bumek [7]3 years ago
7 0
I believe B) consistent and dependent is the answer.

I apologize if it is not correct.

Have a good day :)
tester [92]3 years ago
5 0
The answer is the second one
You might be interested in
Raina must choose a number between 55 and 101 that is a multiple of 2, 8 and 10. Write all the numbers that she could choose. If
Aleonysh [2.5K]

Answer:

The only possible number is 80.

Step-by-step explanation:

The number in question needs to be a multiple of all three of 2, 8, and 10. As a result, it must also be a multiple of the least common multiplier (lcm) of the three number.

Start by finding the least common multiplier of the three numbers.

Factor each number into its prime components:

  • 2 is a prime number itself.
  • 8 = 2^3.
  • 10 = 2 \times 5.

The only prime factors are 2 and 5.

  • The greatest power of 2 among the three numbers is 3.
  • The greatest power of 5 among the three numbers is 1.

Therefore, the least common multiplier of the three number should be the product of 2^3 and 5. That's equal to 2^3 \times 5 = 8 \times 5 = 40.

In other words, the number (or numbers) in question could be written in the form 40\, k, where k is an integer.

The question requires that this number be between 55 and 101. In other words,

55 \le 40\, k \le 101.

The goal is to find the possible values of k. Note that from integer division by 40,

  • 55 = 1 \times 40 + 15, and
  • 101 = 2 \times 40 + 21.

The inequality becomes:

1 \times 40 + 15 \le 40\, k \le 2 \times 40 + 21.

However,

  • 1 \times 40 < 55 = 1 \times 40 + 15, and
  • 2 \times 40 + 21 = 101 < 3 \times 40.

Hence,

1 \times 40 < 1\times 40 + 15 \le 40\, k \le 2 \times 40 + 21 < 3 \times 40.

1 \times 40 < 40\, k < 3 \times 40.

Divide by the positive number 40 to obtain:

1 < k < 3.

Since k is an integers, k = 2.

Indeed, 40 \, k = 80 is between 55 and 101.

Therefore, 80 is the number in question.

5 0
4 years ago
Read 2 more answers
A rectangular of 260 in.³ its width is 5 inches and its length is 8 inches the height of the prism is____in?
Ierofanga [76]

Answer:

B

Step-by-step explanation:

V=LxHxW

260=5x8xH

260=40xH

To find H do 260/40

Answer:6.5

8 0
3 years ago
Read 2 more answers
Determine the common ratio and find the next three terms of the geometric sequence 9,3sqrt3,3
Maru [420]

Answer:

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

Step-by-step explanation:

The geometric progression is:

9, 3 \sqrt{3}, 3...

The first term, a, is 9

To find the common ratio, r, all we have to do is divide a term by its preceding term.

Let us divide the second term by the first:

r = \frac{3\sqrt{3}}{9}\\ \\r = \frac{\sqrt{3}}{3}

That is the common ratio.

Geometric progression is given generally as:

a_n = ar^{(n - 1)}

where a = first term

r = common ratio

a_n = nth term

We need to find the 4th, 5th and 6th terms.

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

5 0
3 years ago
If all the sides of a prism are multiplied by 5, by what factor does the volume increase?
NISA [10]
I'd say increasing each side by 5 increases the volume by a factor of 125 because 5*5*5 = 125.

Example:
A 4*5*6 prism has a volume of 120

Increasing each side by a factor of five
(20*25*30) = 15,000

15,000 / 120 = 125

4 0
3 years ago
Complete the square x^2+6x-16=0
strojnjashka [21]
Let's solve your equation step-by-step:
x^2+6x-16=0
Factor the left side of the equation:(x-2)(x+8)=0
Set factors equal to 0: x-2=0 or x+8=0, x=2 or x=-8
Your answer is x=2 or x=-8, doesn't matter which, both are correct.
Hope this helps!:)
6 0
4 years ago
Read 2 more answers
Other questions:
  • 43. A one sample test for a proportion is being performed. If the critical value is 2.33 and the test statistics is 1.37, a) The
    6·1 answer
  • Please help!!!
    9·2 answers
  • The area of a triangle whose height is 1 more than 6 times its base is 13 square feet. If the base of the triangle is x feet, wh
    5·1 answer
  • Suppose the circumference of a circle is \color{blue}{16\pi}16πstart color blue, 16, pi, end color blue. what is its radius?
    6·1 answer
  • HELP!!!!!!! Me pls I need this now anyone pls
    11·1 answer
  • Can someone help me!!!!!!!
    15·2 answers
  • What geometric shapes can you draw that have no pairs of parallel​ sides
    11·2 answers
  • Which comparison is incorrect?<br><br> -3 &gt; -7<br> -9 &gt; 4<br> -4 &gt; -6<br> 7 &gt; 5
    15·1 answer
  • PLEASE HELP 80 POINTS!! Find the points of equilibria for the following equations and indicate if they are stable or not
    14·1 answer
  • Please help me asap with my grade 11 trigonometry math! I'll give brainliest, please help, thank you. *URGENT*
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!