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11Alexandr11 [23.1K]
3 years ago
12

Point M is the midpoint of segment AB. If AM = 50 – 3x and MB = –20 + 4x, find the value of x. x = -10 x = 10 x = -20 x = 20

Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0
(50-3x)-(-20+4x) = 0

50-3x+20-4x = 0

70-7x = 0

-7x = -70

7x = 70

x = 10

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Please help<br><br> Solve for x and y<br> 60 points!!!!
dlinn [17]

Answer:

see explanation

Step-by-step explanation:

(1)

x + 20 and 45 are vertically opposite angles and are congruent, so

x + 20 = 45 ( subtract 20 from both sides )

x = 25

Similarly 5y and 135 are vertically opposite angles and are congruent

5y = 135 ( divide both sides by 5 )

y = 27

(2)

x + 30 and 70 are vertically opposite angles and are congruent, then

x + 30 = 70 ( subtract 30 from both sides )

x = 40

Similarly y + 50 and 110 are vertically opposite and congruent , so

x + 50 = 110 ( subtract 50 from both sides )

x = 60

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2 years ago
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A rectangular floor measures 10 1/8 feet by 13 3/4 feet. If Emily buys 150 square feet of carpet, will she have enough carpet to
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Yes she will have enough. Here is why.

10 1/8 x 13 3/4 = 139

Therefore the room is 139 square feet. She has 150 square feet of carpet, so she has enough.
6 0
3 years ago
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If f(x) = 5x + 40, what is f(x) when x equals -5?
sladkih [1.3K]
f(x)=5x+40\\\\x=-5\\\\\text{substitute the value of x to the equation}\\\\f(-5)=5\cdot(-5)+40=-25+40=15
3 0
3 years ago
A trimming operation at a local manufacturer produces rods whose length conforms to unifrom distribution with a minimum of 18cm
MariettaO [177]

Answer:

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

Step-by-step explanation:

Given: uniform distribution with min and max values of 18 and 33 respectively.

To find : probability density for upper cumulative frequency i.e 25.8 at least means x\geq25.8  upto 33 cm i.e the maximum limit of function.

Solution:

we have by definition , of uniform distribution

we get , probability density function defines as :

<em>F(x,a,b)= </em>\frac{1}{b-a}<em>   </em>a\leq x\leq b

            =1/(33-18)=1/15=0.0667.

this is probability density function.

here the x=25.8 , a=18 and b=33

for lower cumulative frequency it defines as ;

P(x,a,b)=\frac{x-a}{b-a} =25.8-18/33-18=0.52

for upper cumulative frequency it defines as ;

Q(x,a,b)=b-x/b-a=33-25.8/33-18=0.48

here at least 25.8 cm probability means it should be greater than a value(18cm) hence it is provided by the upper cumulative frequency

i.e. Q(x,a,b)=0.48

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

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Answer:

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Step-by-step explanation:

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