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Andrew [12]
3 years ago
14

What is the difference between the number of solutions for a two-step equation and for a two-step inequality

Mathematics
1 answer:
Sophie [7]3 years ago
7 0

Answer:

A two-step equation is something like:

A*X + B = C

In this case, like in a linear equation, we have only one solution that can be found as:

A*X = C - B

X = (C - B)/A

In the case of a two-step inequality, we have something like:

A*X + B > C

Solving this we get;

A*X >  C - B

X > (C - B)/A

In this case, any value of X that is larger than  (C - B)/A is a solution, so in this case, we have infinite solutions.

That is the difference between the number of solutions for each case, in a two-step equation we have only one, while in the case of the inequality we have infinite.

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7 0
3 years ago
Factor completely 81x8 − 1. (9x4 − 1)(9x4 + 1) (3x2 − 1)(3x2 + 1)(9x4 − 1) (3x2 − 1)(3x2 + 1)(9x4 + 1) (3x2 − 1)(3x2 + 1)(3x2 +
denis-greek [22]

Answer:

(3x^2 - 1)(3x^2 + 1)(9x^4 + 1).

Step-by-step explanation:

Using the identity for the difference of 2 squares;

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we put a^2 = 81x^8 and b^2 = 1  giving

a = 9x^4 and b = 1, so:

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Applying the difference of 2 squares to 9x^4 - 1:

= (3x^2 - 1)(3x^2 + 1)(9x^4 + 1).

6 0
3 years ago
Solve:<br><br> (√x + 2)(√x - 2) = 0<br><br> x = ?
Aloiza [94]

Answer: x = 4

Step-by-step explanation:

(√x + 2)(√x - 2) = 0

√x*√x - 2√x + 2√x -4 = 0

x - 0 - 4 = 0

x = 4

3 0
2 years ago
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Novosadov [1.4K]

Answer:

1/3

Step-by-step explanation:

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5 0
3 years ago
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