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shtirl [24]
3 years ago
10

.What is the percent increase from 1987 to today?

Mathematics
1 answer:
kozerog [31]3 years ago
7 0

Answer:

In other words, $100 in 1987 is equivalent in purchasing power to about $227.09 in 2020, a difference of $127.09 over 33 years. The 1987 inflation rate was 3.65%. The current inflation rate (2019 to 2020) is now 2.49% 

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How is the Recursive Formula used in real life
OlgaM077 [116]

Answer:

People often sort stacks of documents using a recursive method. For example, imagine you are sorting 100 documents with names on them. First place documents into piles by the first letter, then sort each pile. Looking up words in the dictionary is often performed by a binary-search-like technique, which is recursive.

Step-by-step explanation:

This is just an example.

If this helps please mark as brainliest

4 0
2 years ago
On a scale drawing with a scale of 1/20, the height of the building is 8 inches. How tall is the actual building in feet?
Alecsey [184]
That means its downgraded to 1/20 of actual height, let actual height is x. Then 
(1/20) * x = 8, x = 20 * 8 = 160, actual height = 160 inch
160 inch = 160/12 feet = 13 1/3 feet or 13.333 feet.
3 0
3 years ago
In need help with this finding function
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4 0
2 years ago
What is the y-intercept of the function f(x) = –negative StartFraction 2 Over 9 EndFraction.x + ?
worty [1.4K]

fdfghjkAdf negativo

Step-by-step explanation:

7 0
3 years ago
A. Find the linear approximating polynomial for the following function centered at the given point a. b. Find the quadratic appr
Tema [17]

Answer:

a. p1(x) = 2 - x

b. p2(x) = x² - 3*x + 3

c. p1(0.97) = 1.03; p2(0.97) = 1.0309

Step-by-step explanation:

f(x) = 1/x

f'(x) =  -1/x²

f''(x) = 2/x³

a = 1

a. The linear approximating polynomial is:

p1(x) = f(a) + f'(a)*(x - a)

p1(x) = 1/1 + -1/1² * (x - 1)

p1(x) = 1 - x + 1

p1(x) = 2 - x

b. The quadratic approximating polynomial is:

p2(x) = p1(x) + 1/2 * f''(a)*(x - a)²

p2(x) = 2 - x + 1/2 * 2/1³ * (x - 1)²

p2(x) = 2 - x + (x - 1)²

p2(x) = 2 - x + x² - 2*x + 1

p2(x) = x² - 3*x + 3

c. approximate 1/0.97 using p1(x)

p1(0.97) = 2 - 0.97 = 1.03

approximate 1/0.97 using p2(x)

p2(0.97) = 0.97² - 3*0.97 + 3 = 1.0309

7 0
3 years ago
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