All categories

3 years ago

Is 6.78778777 irrational?

1 answer:

7 0

No its not because its a repeating decimal for a number to be a irrational number it has to be non terminating or non repeating

You might be interested in

This is all I need because its 55% of my grade on this practice, please help ty.

Dvinal [7]

Answer:

$18+2x=42$ , $2+18x=42$ , $42-2x=18$ , $2(x+18)=42$ , $x+42=18+4x$

Step-by-step explanation:

First question:

He starts with 18, gains 2 every week, and needs 42. This means the equation is $18+2x=42$ .

Second question:

He starts with 2, gains 18 every week, and needs 42. This means the equation is $2+18x=42$ .

Third question:

It starts with 42, loses 2 every day, and needs 18. This means the equation is $42-2x=18$ .

Fourth question:

Each friend has a total bill of 18+x, there are 2 friends, and they need 42. This means the equation is $2(x+18)=42$ .

The only answer left is $x+42=18+4x$ , so that's the answer to the fifth problem.

6 0

3 years ago

Deanna uses only fruit juice and sparkling water to make punch for a school dance. She uses 6 liters of fruit juice. She uses 0.

Softa [21]

Answer: 3.6 liters

Step-by-step explanation:

You know that:

- She uses 6 liters of fruit juice.

- She uses 0.6 as much sparkling water as fruit juice.

Therefore, let's call x the amount of fruit punch she made.

Keeping the above on mind, you can solve the problem by multiplying the 6 liter of fruit juice she uses by 0.6.

Therefore the result is:

$x=(6liter)(0.6)\\x=3.6liters$

3 0

3 years ago

Read 2 more answers

The local public transport authority is conducting research into commuter behaviour. A previous census indicated that the mean c

kondor19780726 [428]

Answer:

$H_0:\mu = 45$ and $H_a:\mu < 45$

$T = 34.88$

The null hypothesis is not rejected

Step-by-step explanation:

Given

Random sample of 50 commuter times

Solving (a): The null and alternate hypothesis

From the question, a previous census shows that:

$\mu =45$ and $\sigma= 9.1$

This is the null hypothesis i.e.

$H_0:\mu = 45$

Reading further, a new test was to show whether the average has decreased.

This is the alternate hypothesis, and it is represented as:

$H_a:\mu < 45$

Solving (b) and (c): The test statistic (T).

This is calculated using:

$T = \frac{\mu}{\sigma/\sqrt n}$

In this case:

$n = 50$ $\mu =45$ and $\sigma= 9.1$

So:

$T = \frac{45}{9.1/\sqrt{50}}$

$T = \frac{45}{9.1/7.07}$

$T = \frac{45}{1.29}$

$T = 34.88$

Solving (c): Accept or reject null hypothesis

$\alpha = 0.05$

First calculate the degrees of freedom (df)

$df = n - 1 = 50 - 1$

$d f = 49$

From the t distribution table,

At: $d f = 49$ , $\alpha = 0.05$ and $T = 34.88$

the t score is:

$p = 1.676$

$p > 0.05$

<em>So, the null hypothesis is not rejected</em>

7 0

3 years ago

Please help! asap! thank you so much! I have photos attached!

schepotkina [342]

Answer:

Step-by-step explanation:

Given problems are absolute value problems, So we need to plug the values of given parameters and get the final result.

We have given here,

a =-2 , b = 3 , c = -4 and d = -6

Now we know that An absolute function always gives a positive value.

Let's apply this strategy in the given problems.

1. ║a+b║

Plug a= -2 and b = 3

We get, ║-2+3║=║1║= 1

2. 5║c+b║

Plug c= -4 and b=3

i.e. 5║-4 + 3║= 5║-1║=5×1 = 5

3. a+b║c║

Plug values a= -2 , b=3 and c=-4

i.e -2 +3║-4║ = -2 + 3×4 = -2 + 12 = 10

4. ║a+c║÷(-d)

i.e ║-2 + (-4)║÷(-6) = ║-6║÷(-6) = 6÷(-6) = -1

5. 3║a+d║+b

i.e 3║-2+(-6)║+3 = 3║-8║+3 = 3×8 +3 = 27

4 0

3 years ago

HELPPPPPPP ME PLEASEE

Svetlanka [38]

Answer:

Step-by-step explanation:

Since they are consecutive angles

You would subtract 180 from 135 to get 45 Measure 2 is 45

5 0

3 years ago

Read 2 more answers