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PIT_PIT [208]
3 years ago
14

Write a method that accepts a string as an argument and checks it for proper capitalization and punctuation. The method should d

etermine if the string begins with an uppercase letter and ends with a punctuation mark. The method should return true if the string meets the criteria; otherwise it should return false .
Computers and Technology
1 answer:
Contact [7]3 years ago
6 0

Answer:

The method in Python is as follows:

def checkStr(strng):

   if strng[0].isupper() and strng[-1] == "?":

       return True

   else:

       return False

Explanation:

This defines the method

def checkStr(strng):

This checks if the first character i upper and if the last is "??

   if strng[0].isupper() and strng[-1] == "?":

If the condition is true, the function returns true

       return True

Else, it returns false

<em>    else:</em>

<em>        return False</em>

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torisob [31]

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I hope this helps!

6 0
3 years ago
Recursively computing the sum of the first n positive odd integers, cont. About (a) Use induction to prove that your algorithm t
julia-pushkina [17]

The recursive function would work like this: the n-th odd number is 2n-1. With each iteration, we return the sum of 2n-1 and the sum of the first n-1 odd numbers. The break case is when we have the sum of the first odd number, which is 1, and we return 1.

int recursiveOddSum(int n) {

 if(2n-1==1) return 1;

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}

To prove the correctness of this algorithm by induction, we start from the base case as usual:

f(1)=1

by definition of the break case, and 1 is indeed the sum of the first odd number (it is a degenerate sum of only one term).

Now we can assume that f(n-1) returns indeed the sum of the first n-1 odd numbers, and we have to proof that f(n) returns the sum of the first n odd numbers. By the recursive logic, we have

f(n)=f(n-1)+2n-1

and by induction, f(n-1) is the sum of the first n-1 odd numbers, and 2n-1 is the n-th odd number. So, f(n) is the sum of the first n odd numbers, as required:

f(n)=\underbrace{\underbrace{f(n-1)}_{\text{sum of the first n-1 odds}}+\underbrace{2n-1}_{\text{n-th odd}}}_{\text{sum of the first n odds.}}

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3 years ago
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Answer:

I think u had forgot to mention the statements.

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Answer:

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I believe the answer is C the motherboard!  
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