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Dahasolnce [82]
3 years ago
13

an isosceles triangle has a vertex angle of 21.21 degrees. two sides of the triangle are each 17.91 ft long. whats the area of t

he triangle
Mathematics
1 answer:
lubasha [3.4K]3 years ago
7 0

Answer:

The area of triangle is A=58.02\ ft^{2}

Step-by-step explanation:

Let

B -----> the measure of the vertex angle of the isosceles triangle ABC

a and c -----> the two congruent sides of the isosceles triangle ABC

we know that

The area of a triangle applying the law of sines is equal to

A=\frac{1}{2}(a)(c)sin(B)

we have

a=c=17.91\ ft

B=21.21\°

substitute in the formula

A=\frac{1}{2}(17.91)(17.91)sin(21.21\°)

A=58.02\ ft^{2}

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Read 2 more answers
X+y=4<br> X-3y=12<br> Graph?
AlekseyPX
I'll solve it algebraically


x+y=4
x-3y=12

multiply first equatoin by -1 and add to second

-x-y=-4
<u>x-3y=12 +</u>
0x-4y=8


-4y=8
divide both sides by -4
y=-2

sub back

x+y=4
x+-2=4
add 2 to both sides
x=6

x=6
y=-2
(6,-2)
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