Question

an isosceles triangle has a vertex angle of 21.21 degrees. two sides of the triangle are each 17.91 ft long. whats the area of the triangle

Answer 1

Answer:

The area of triangle is $A=58.02\ ft^{2}$

Step-by-step explanation:

Let

B -----> the measure of the vertex angle of the isosceles triangle ABC

a and c -----> the two congruent sides of the isosceles triangle ABC

we know that

The area of a triangle applying the law of sines is equal to

$A=\frac{1}{2}(a)(c)sin(B)$

we have

$a=c=17.91\ ft$

$B=21.21\°$

substitute in the formula

$A=\frac{1}{2}(17.91)(17.91)sin(21.21\°)$

$A=58.02\ ft^{2}$