None of the above are equivalent to -6(b+2)+8
400$
Explanation:
In 1992, the price is 28000$ and 9600$ in 1996 so in 4 years the value the car lost is 18400$
Dividing 18400 by 4 years we get 4600 depreciation value per year.
Between 1996 and 1998 there is 2 years
So in 1998 the value of the car will be:
9600 (value in 1996) - 2x4600 = 400$
assume you want a line that goes through the given point and parallel to the given line. A line that is parallel to y=2/3 x + 5 will have the same slope. slope of that line is 2/3...the number in front of the x. So our new line will have slope of 2/3. now we need the y-intercept. To find that start with a slope intercept equation y=mx+b plug in the slope that we already know...it goes in for x...will be the number in front of x y= 2/3 x + b. now all we need is a number to plug in for the "b" and we will have it. to get the "b"...start with the part you already know. y = 2/3 x + b use the point they gave you...(-3,1)...and get x and y from it x will be -3 and y will be 1 plug that in 1= 2/3 ( -3) + b now we solve for b 1 = -2 + b 3 = b now we have the b we need y = 2/3 x + b y = 2/3 x + 3
The complete question is
<span>Sarah rides her horse for 2 1/6 hrs with a constant speed of 6 km/hr and then for another 2 hours and 5 minutes with a constant speed of 12 km/hr what is her average speed for the total trip?</span>
we know that
speed=distance/time
1) Sarah rides her horse for 2 1/6 hrs with a constant speed of 6 km/hr
time=2 1/6 hrs----> 13/6 hrs
speed=6 km/h
distance=speed*time----> 6*(13/6)---> 13 km
2)for another 2 hours and 5 minutes with a constant speed of 12 km/hr
time=2hrs+5 minutes----> 2+(5/60)--> 125/60 hrs
speed=12 km/hrs
distance=speed*time----> 12*(125/60)---> 25 km
3) find the average speed for the total trip
total distance=13 km+25 km----> 38 km
total time=(13/6)+(125/60)----> (10*13+125)/60----> 4.25 hours
speed=38/4.25----> 8.94 km/hrs
the answer is
8.94 km/hrs
1:4 is you answer. 4-3 is 1 and you do the same to 7
