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Irina18 [472]
3 years ago
15

Please help!! 30 points if you answer. Answer ASAP!!Which word phrases can be modeled by the expression? Choose exactly two answ

ers that are correct. A.ten less than the quotient of a number and 7 B.ten deducted from the product of a number and 7 C.the difference of a number and 10 divided by 7 D.the quotient of a number and 7, reduced by 10
Mathematics
1 answer:
shutvik [7]3 years ago
8 0
N=number A: n divided by 7 minus 10 B: n times 7 minus 10 C: 10 divided by 7 minus n D: n divided by 7 minus 10
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Find the first five terms of the sequence defined below, where n represents the position of a
SOVA2 [1]

Answer:

Your answer is going to be 4, 7, 10, 13, 16

Step-by-step explanation:

n=1,  3*1+1=4

n=2,  3*2+1=7

n=3,  3*3+1=10

n=4,  3*4+1=13

n=5,  3*5+1=16

6 0
3 years ago
The expression 1.01*1.005(^t) gives the amount of money, in thousands of dollars, in Carter's savings account (t) years after he
dimulka [17.4K]

Answer:

Step-by-step explanation:

Carter's savings account had $1,010 it when he opened it.

4 0
3 years ago
Tevon,leah,and beth are playing a computer game. Trevon scored -8. Beth's score was 3/4 of trever's score, and leah's score was
faust18 [17]

Answer:

Trevon scored -8.

Beth's score was 3/4 of trever's score = -8 *3/4 = -6

leah's score was 1/4 of beth's score. = -6 *1/4 = -1.5

Leah's score was -1.5


8 0
3 years ago
4. Solve the equation for the given variable. For each step. Identity the property used to convert the equation. 22x + 11 = 4x -
Andrei [34K]

Answer:

x=-1

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Someone ask me to solve this.
Semenov [28]
X=2h, y=3k

Substitute these values into equations.

y+2x = 4 ------> 3k+2*2h=4 ----->  3k +4h =4

2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1

We have a system of equations now.

 3k +4h =4          ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1

2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0

4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0

(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0

Denominator cannot be = 0
4h(2-2h)≠0

Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4  or h=-1

Check which
4h(2-2h)≠0
1) h= 3/4  , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.

h=3/4, then  3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then  3k = 4-4*(-1) =8 , 3k=8, k=8/3 

So,
if h=3/4, then  k=1/3,
and if h=-1, then  k=8/3 .




6 0
2 years ago
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