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Artist 52 [7]
2 years ago
7

Help i will give an award!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Yuki888 [10]2 years ago
8 0

Answer:

x = 3

Step-by-step explanation:

(3^x)^1/2/3^ 1/2 = 3

x = 3

<u><em></em></u>

<u><em>The Kid Laroi</em></u>

Grace [21]2 years ago
6 0

Answer: Plug in answers work backwards; or learn log to get rid of powers

Step-by-step explanation: save time on your test by cheating yourself of knowledge

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HELP PLEASE ASAP
Vladimir79 [104]

By using dimensional analysis, this problem can be simple.


100cm * \frac{1m}{100cm} = 1m

B

4 0
3 years ago
Adult male heights have a normal probability distribution with a mean of 70 inches and a standard deviation of 4 inches.
nexus9112 [7]

Answer: 0.84134

Step-by-step explanation:

We need to find the z-score for the given information first since this will help us find the probability. The formula for this is

Z score = \frac{x - \mu}{\sigma}

We have

x = 66 inches (the raw score)

\mu = 70 inches (the population mean)

\sigma = 4 inches (the standard deviation)

This gives

Z score = \frac{x - \mu}{\sigma} = \frac{66-70}{4} = -1

If you use a calculator, or a Z-score table then P(x > Z) is just P(Z > -1) which gives a probability of 0.84134.

7 0
2 years ago
I need help........ PLEASE HELP!!!!!!!!!!!!!!! This is confusing me.... I don't understand it. I really need help with this. If
Ann [662]

Answer:

Step-by-step explanation:

We know that a triangle equals to 180 degrees.

(2x+24)+(4x+43)+(x^2+1)=180

the awnser to this is x=8.

You plug in 8 into x

Angle 1: 2(8+24) --> 40

Angle 2: 4(8+43) -->75

Angle 3: (8^2+1)  -->65

Check your work: add values together 40+75+65=180

8 0
3 years ago
Need help getting stuck on this problem
stepan [7]

Answer:

  • Variable x in first equation

Step-by-step explanation:

<u>Given system</u>

  • x = 5y - 1
  • x + 2y = 13

Variables in this system are x and y.

Isolating a variable means rearranging the equation so that a variable of our interest is on its own in one side of the equal sign.

We see <u>variable x is isolated </u>in the first equation.

In the second equation both of the variables are on the same side so they are not isolated.

3 0
3 years ago
Find <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bdy%7D%7Bdx%7D%20" id="TexFormula1" title=" \frac{dy}{dx} " alt=" \frac{d
nataly862011 [7]

Answer:

\displaystyle y' = 2x + 3\sqrt{x} + 1

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Anything to the 0th power is 1
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Rule [Root Rewrite]:                                                                     \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}<u> </u>

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                    \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle y = (x + \sqrt{x})^2<em />

<em />

<u>Step 2: Differentiate</u>

  1. Chain Rule:                                                                                                        \displaystyle y' = 2(x + \sqrt{x})^{2 - 1} \cdot \frac{d}{dx}[x + \sqrt{x}]
  2. Rewrite [Exponential Rule - Root Rewrite]:                                                     \displaystyle y' = 2(x + x^{\frac{1}{2}})^{2 - 1} \cdot \frac{d}{dx}[x + x^{\frac{1}{2}}]
  3. Simplify:                                                                                                             \displaystyle y' = 2(x + x^{\frac{1}{2}}) \cdot \frac{d}{dx}[x + x^{\frac{1}{2}}]
  4. Basic Power Rule:                                                                                             \displaystyle y' = 2(x + x^{\frac{1}{2}}) \cdot (1 \cdot x^{1 - 1} + \frac{1}{2}x^{\frac{1}{2} - 1})
  5. Simplify:                                                                                                             \displaystyle y' = 2(x + x^{\frac{1}{2}}) \cdot (1 + \frac{1}{2}x^{-\frac{1}{2}})
  6. Rewrite [Exponential Rule - Rewrite]:                                                              \displaystyle y' = 2(x + x^{\frac{1}{2}}) \cdot (1 + \frac{1}{2x^{\frac{1}{2}}})
  7. Multiply:                                                                                                             \displaystyle y' = 2[(x + x^{\frac{1}{2}}) + \frac{x + x^{\frac{1}{2}}}{2x^{\frac{1}{2}}}]
  8. [Brackets] Add:                                                                                                 \displaystyle y' = 2(\frac{2x + 3x^{\frac{1}{2}} + 1}{2})
  9. Multiply:                                                                                                             \displaystyle y' = 2x + 3x^{\frac{1}{2}} + 1
  10. Rewrite [Exponential Rule - Root Rewrite]:                                                     \displaystyle y' = 2x + 3\sqrt{x} + 1

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

4 0
3 years ago
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