Ask question

Ask question

All categories

3 years ago

5

A buyer for a department store orders sweaters about 6 months before the winter season. The store plans to hold a March clearanc

e sale to sell any surplus goods by February 29. Each piece costs $100 per pair and sells for $120 per pair. At the sale price of $60 per pair, it is expected that any remaining stock can be sold during the March sale. Assume that a uniform probability distribution ranging from 250 to 450 items describes the demand. The expected demand is 300. In the context of the single period inventory system, the optimal order size Q must satisfy the condition _____.

1 answer:

lilavasa [31]3 years ago

7 0

Answer:

P(demand ≤ Q*) = 1/3

Step-by-step explanation:

You might be interested in

Solve the equations

ASHA 777 [7]

Answer:

(1)The value of x is -9 .

Option (B) is correct .

(2)The value of x is 13 .

Option (A) is correct .

(3)The value of the x is 11 .

Option (D) is correct .

(4) The value of the x is -15 .

Option (A) is correct .

(5)The value of the x is -11 .

Option (C) is correct .

Step-by-step explanation:

First Part

As given

4x = -36

$x = \frac{-36}{4}$

x = -9

Therefore the value of x is -9 .

Option (B) is correct .

Second Part

As given

5x - 15 = 50

5x = 50 + 15gg

5x = 65

$x = \frac{65}{5}$

x = 13

Therefore the value of x is 13 .

Option (A) is correct .

As given

4(x+2)-17=35

4x + 8 - 17 = 35

4x = 35 + 17 - 8

4x = 44

$x = \frac{44}{4}$

x = 11

Therefore the value of the x is 11 .

Option (D) is correct .

Fourth Part

As given

6x+12=4x-18

6x-4x = -12-18

2x = -30

$x = \frac{-30}{2}$

x = -15

Therefore the value of the x is -15 .

Option (A) is correct .

Fifth Part

As given

$\frac{1}{2}(4x-10)+5=x-11$

Simplify the above

4x-10+5×2 = 2x-22

4x-10+10= 2x-22

4x-2x = -22

2x=-22

$x = \frac{-22}{2}$

x = -11

Therefore the value of the x is -11 .

Option (C) is correct .

5 0

4 years ago

Read 2 more answers

Alex73 [517]

Your answer is A. Bro

8 0

3 years ago

Read 2 more answers

the number of subscriptions to an interior design magazine was 16,450 in 1996. Since then, the number of subscriptions has incre

babunello [35]

Answer:

49,744.8 so round up to 49,745

Step-by-step explanation:

4 0

4 years ago

Please help me and we should use laws of exponents

elena55 [62]

Answer:

3.b

$(\frac{8}{3})^{2x+1} *(\frac{8}{3})^{5} =(\frac{8}{3}) ^{x+2}\\\\(\frac{8}{3})^{2x+1 +5} =(\frac{8}{3}) ^{x+2}\\\\\\2x +6 = x+2\\x = -4$

i hope question 3.a. is 5^x ÷ 5^-3 = 5^5

3.a.

$\frac{5^x}{5^{-3}} = 5^5\\\\5^ {x+3} = 5^5\\\\x+3 = 5\\x =2$

6 0

3 years ago

Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers

lidiya [134]

Answer:

$6-3\sqrt{3}$

If you compare this to $a+b\sqrt{3}$ , then $a=6$ and $b=-3$ .

Step-by-step explanation:

We are given $x=\sqrt{3}-1$ and we are asked to find the value of $x^2-x+1$ .

So we will need to find $x^2$ .

$x=\sqrt{3}-1$

Square both sides:

$x^2=(\sqrt{3}-1)^2$

Expand using identity: $(x-a)^2=x^2-2ax+a^2$ .

$x^2=(\sqrt{3})^2-2(\sqrt{3})(1)+1^2$

$x^2=3-2\sqrt{3}+1$

$x^2=4-2\sqrt{3}$

Let's go back to the full $x^2-x+1$ .

$x^2-x+1$

$(4-2\sqrt{3})-(\sqrt{3}-1)+1$

$4-2\sqrt{3}-\sqrt{3}+1+1$

$6-3\sqrt{3}$

If you compare this to $a+b\sqrt{3}$ , then $a=6$ and $b=-3$ .

5 0

4 years ago