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quester [9]
4 years ago
5

Solve the equations

Mathematics
2 answers:
gregori [183]4 years ago
7 0

1. The value of x is \boxed{x =  - 9}. Option (B) is correct.

2. The value of x is \boxed{x = 13}. Option (A) is correct.

3. The value of x is \boxed{x = 11}. Option (D) is correct.

4. The value of x is \boxed{x = - 15}. Option (A) is correct.

5. The value of x is \boxed{x = - 11}. Option (C) is correct.

Further explanation:

Always use the PEDMAS rule to solve the grouping of multiplication, addition, subtraction and division.

Here, P is parenthesis, E is exponents, M is multiplication, D is division, A is addition and S is subtraction.

Explanation:

Part (1)

The given equation is 4x =  - 36

Solve the above expression to obtain the value of x.

\begin{aligned}4x &= - 36\\\frac{{4x}}{4}&= \frac{{ - 36}}{4}\\x&= - 9\\\end{aligned}

The value of x is \boxed{x =  - 9}.

Part (2)

The equation is 5x - 15 = 50.

Solve the above expression to obtain the value of x.

\begin{aligned}5x - 15 &= 50\\5x &= 65\\x&= \frac{{65}}{5}\\x&= 13\\\end{aligned}

The value of x is \boxed{x = 13}.

Part (3)

The equation is 4\left( {x + 2} \right) - 17 = 35.

Solve the above expression to obtain the value of x.

\begin{aligned}4\left( {x + 2} \right) - 17 &= 35\\4x + 8 &= 35 + 17 \\4x &= 52- 8\\4x &= 44\\x &= 11\\\end{aligned}

The value of x is \boxed{x = 11}.

Part (4)

The equation is 6x + 12 = 4x - 18.

Solve the above expression to obtain the value of x.

\begin{aligned}6x + 12 &= 4x - 18\\6x - 4x &=  - 18 - 12\\2x &= - 30\\x &= \frac{{ - 30}}{2}\\x &=- 15\\\end{aligned}

The value of x is \boxed{x = - 15}.

Part (5)

The equation is \dfrac{1}{2}\left( {4x - 10} \right) + 5 = x - 11

Solve the above expression to obtain the value of x.

\begin{aligned}\frac{1}{2}\left( {4x - 10} \right) + 5 &= x - 11\\\frac{1}{2}\left( {4x - 10} \right) &= x - 11 - 5\\\left( {4x - 10} \right) &= 2\left( {x - 16} \right)\\4x - 10 &= 2x - 32\\4x - 2x &= - 32 + 10\\2x &= - 22\\x&= - 11\\\end{aligned}

The value of x is \boxed{x = - 11}.

Learn more

  1. Learn more about the polynomial brainly.com/question/12996944
  2. Learn more about logarithm model brainly.com/question/13005829
  3. Learn more about the product of binomial and trinomial brainly.com/question/1394854

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Number system

Keywords: factor, factorization, 4x = -36, 5x-15=50, 4(x+2)-17=35, equation, value of x, division, multiplication, subtraction, solve the equation, solution, linear equation, line

ASHA 777 [7]4 years ago
5 0

Answer:

(1)The value of x is -9 .

Option (B) is correct .

(2)The value of x is 13 .

Option (A) is correct .

(3)The value of the x is 11 .

Option (D) is correct .

(4) The value of the x is -15 .

Option (A) is correct .

(5)The value of the x is -11 .

Option (C) is correct .

Step-by-step explanation:

First Part

As given

4x = -36

x = \frac{-36}{4}

x = -9

Therefore the value of x is -9 .

Option (B) is correct .

Second Part

As given

5x - 15 = 50

5x = 50 + 15gg

5x = 65

x = \frac{65}{5}

x = 13

Therefore the value of x is 13 .

Option (A) is correct .

As given

4(x+2)-17=35

4x + 8 - 17 = 35

4x = 35 + 17 - 8

4x = 44

x = \frac{44}{4}

x = 11

Therefore the value of the x is 11 .

Option (D) is correct .

Fourth Part

As given

6x+12=4x-18

6x-4x = -12-18

2x = -30

x = \frac{-30}{2}

x = -15

Therefore the value of the x is -15 .

Option (A) is correct .

Fifth Part

As given

\frac{1}{2}(4x-10)+5=x-11

Simplify the above

4x-10+5×2 = 2x-22

4x-10+10= 2x-22

4x-2x = -22

2x=-22

x = \frac{-22}{2}

x = -11

Therefore the value of the x is -11 .

Option (C) is correct .

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The~average~rate~of~change~of~the~given~quadratic~function~on~the interval~0 ≤ x ≤4 is~the~slope~of~the~secant~line~connecting~the~points~(0,f(0))~and~(4,f(4)).

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<img src="https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BE%7D%7B%20%5Csqrt%7BR%20%7B%7D%5E%7B2%7D%20%2B%20W%20%7B%7D%5E%7B2%7D%20L%
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Answer:

R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Step-by-step explanation:

Squaring both sides of equation:

     I^2 = (ER)^2/(R^2 + (WL)^2)

<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)

<=>(ER)^2 - (IR)^2 = (IWL)^2

<=> R^2(E^2 - I^2) = (IWL)^2

<=> R^2 = (IWL)^2/(E^2 - I^2)

<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Hope this helps!

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